An iron nail with a mass of 12 g absorbs 15 J of heat. If the nail was initially at 28 °C, what is its final temperature?

Solution 81P :

Step 1:

Given :

mass of iron nail = 12 g

Heat absorbed = 15 J.

Initially temperature of nail = 28 °C

Final temperature = ?

To calculate the final temperature, we need specific heat of iron :

The Specific Heat of Iron = 0.440 J/g/°C (K).

Now, let’s calculate the change in temperature () :

Q(Amount of heat) = m (mass) C(Specific heat) (Temperature change)

15J = 12g 0.44J/g/°C

15J = 5.28

=

= 2.84°C