An iron nail with a mass of 12 g absorbs 15 J of heat. If the nail was initially at 28 °C, what is its final temperature?
Solution 81P :
mass of iron nail = 12 g
Heat absorbed = 15 J.
Initially temperature of nail = 28 °C
Final temperature = ?
To calculate the final temperature, we need specific heat of iron :
The Specific Heat of Iron = 0.440 J/g/°C (K).
Now, let’s calculate the change in temperature () :
Q(Amount of heat) = m (mass) C(Specific heat) (Temperature change)
15J = 12g 0.44J/g/°C
15J = 5.28
Textbook: Introductory Chemistry
Author: Nivaldo J Tro
The answer to “An iron nail with a mass of 12 g absorbs 15 J of heat. If the nail was initially at 28 °C, what is its final temperature?” is broken down into a number of easy to follow steps, and 27 words. Since the solution to 81P from 3 chapter was answered, more than 4698 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 81P from chapter: 3 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. This full solution covers the following key subjects: nail, iron, heat, initially, final. This expansive textbook survival guide covers 19 chapters, and 2045 solutions.