An iron nail with a mass of 12 g absorbs 15 J of heat. If the nail was initially at 28 °C, what is its final temperature?
Solution 81P :
mass of iron nail = 12 g
Heat absorbed = 15 J.
Initially temperature of nail = 28 °C
Final temperature = ?
To calculate the final temperature, we need specific heat of iron :
The Specific Heat of Iron = 0.440 J/g/°C (K).
Now, let’s calculate the change in temperature () :
Q(Amount of heat) = m (mass) C(Specific heat) (Temperature change)
15J = 12g 0.44J/g/°C
15J = 5.28