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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 2 - Problem 59p
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 2 - Problem 59p

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# Correct any answers that have the incorrect number of significant figures.(a) 34.00 ×567 ISBN: 9780321910295 34

## Solution for problem 59P Chapter 2

Introductory Chemistry | 5th Edition

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Problem 59P

Problem 59P

Correct any answers that have the incorrect number of significant figures.

(a) 34.00 ×567 ÷ 4.564 = 4.2239 ×103

(b) 79.3 ÷ 0.004 ×35.4 = 7 ×105

(c) 89.763 ÷ 22.4581 = 3.997

(d) (4.32 × 1012) ÷ (3.1 × 10−4) = 1.4 × 1016

Step-by-Step Solution:

Solution 59P

Step 1:

(a) 34.00 ×567 ÷ 4.564 = 4.2239 ×103

34.00 ×567 =19278

Here the least number of significant figures is two , hence the above answer is rounded off as 19.

Now, 19÷ 4.564 =4.16301

Here the least number of significant digits are two , hence the above answer is rounded off as  4.2 104

Thus the given answer 4.2239 ×103 is incorrect.

Step 2 of 4

Step 3 of 4

##### ISBN: 9780321910295

Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. Since the solution to 59P from 2 chapter was answered, more than 845 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 59P from chapter: 2 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. This full solution covers the following key subjects: answers, any, correct, figures, incorrect. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. The answer to “Correct any answers that have the incorrect number of significant figures.(a) 34.00 ×567 ÷ 4.564 = 4.2239 ×103(b) 79.3 ÷ 0.004 ×35.4 = 7 ×105(c) 89.763 ÷ 22.4581 = 3.997(d) (4.32 × 1012) ÷ (3.1 × 10?4) = 1.4 × 1016” is broken down into a number of easy to follow steps, and 41 words.

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