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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 11 - Problem 26p
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 11 - Problem 26p

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# Perform each conversion.(a) 1 .06 atm to millimeters of mercury(b) 95,422 Pa to ISBN: 9780321910295 34

## Solution for problem 26P Chapter 11

Introductory Chemistry | 5th Edition

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Problem 26P

PROBLEM 26P

Perform each conversion.

(a) 1 .06 atm to millimeters of mercury

(b) 95,422 Pa to millimeters of mercury

(c) 22.3 psi to torr

(d) 35.78 in. Hg to millimeters of mercury

Step-by-Step Solution:
Step 1 of 3

Solution 26P

Here, we are going to convert the unit.

(a) 1 .06 atm to millimeters of mercury

1 atm = 760 mmHg

Conversion factor = Thus, 1 .06 atm  = 1 .06 atm x = 805.6 mm Hg

Therefore, 1.06 atm = 805.6 mm Hg

(b) 95,422 Pa to millimeters of mercury

1 mmHg = 133.322365 pa

Conversion factor = Thus, 95,422 Pa  = 95,422 Pa x =  715.725 mm Hg

Therefore, 95,422 Pa  = 715.725 mm Hg

(c) 22.3 psi to torr

1 psi = 51.71484 torr

Conversion factor = Thus 22.3 psi x = 1153.24 torr

Therefore, 22.3 psi  = 1153.24 torr

(d) 35.78 in. Hg to millimeters of mercury

We know

1 inHg = 25.399904 mmHg

Conversion factor = Thus, 35.78 in. Hg x = 908.808 mm Hg

Therefore, 35.78 in. Hg  = 908.808 mm Hg

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321910295

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