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# Calculate the mass of glucose (C6H12O6) in a 105-mL sample of a 1.02 M glucose solution ISBN: 9780321910295 34

## Solution for problem 72P Chapter 13

Introductory Chemistry | 5th Edition

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Problem 72P

Problem 72P

Calculate the mass of glucose (C6H12O6) in a 105-mL sample of a 1.02 M glucose solution.

Step-by-Step Solution:
Step 1 of 3

Solution: here, we are going to calculate the mass of glucose(C6H12O6) in the sample solution.

Step1:

Molarity(M) is defined as number of moles of solute dissolved in one litre (or one cubic decimetre) of solution.

Moles of solute

Molarity = -------------------------------         ------(1)

Volume of solution in litre

Step2:

In the above problem,

Volume of the solution = 105 mL = 105 / 1000 L = 0.105 L                [1000 mL = 1 L]

Molarity of the solution = 1.02 M

Substituting the values in equation (1), we get,

1.02 M = moles of C6H12O6 / 0.105 L

Therefore, moles of C6H12O6 = 1.02 M x 0.105 L

= 0.1071 mol

Step3:

1 mol C6H12O6 = molar mass of C6H12O6

0.1071 mol C6H12O6 = 0.1071 x molar mass of C6H12O6

= 0.1071 x 180.16 g/mol

= 19.295 g.

Thus, the mass of C6H12O6 is 19.295 g.

-------------------------------

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321910295

Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The full step-by-step solution to problem: 72P from chapter: 13 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Since the solution to 72P from 13 chapter was answered, more than 1863 students have viewed the full step-by-step answer. This full solution covers the following key subjects: glucose, mass, calculate, sample, solution. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. The answer to “Calculate the mass of glucose (C6H12O6) in a 105-mL sample of a 1.02 M glucose solution.” is broken down into a number of easy to follow steps, and 16 words.

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Calculate the mass of glucose (C6H12O6) in a 105-mL sample of a 1.02 M glucose solution