Solution Found!
How many liters of a 0.500 M sucrose (C12H22O11) solution contain 1.5 kg of sucrose?
Chapter 13, Problem 75P(choose chapter or problem)
Get Unlimited Answers! Check out our subscriptions
Questions & Answers
QUESTION:
How many liters of a 0.500 M sucrose \(\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right)\) solution contain 1.5 kg of sucrose?
ANSWER:
Step 1 of 3
Molarity of the solution can be calculated by the following formula;
\(\text { Molarity }=\frac{\text { Number of moles of sucrose }}{\text { Volume of solution }}\)
Rearrange the formula (1)
\(\text { Volume of solution }=\frac{\text { Moles of sucrose }}{\text { Molarity }}\)
Become a subscriber and get unlimited answers!