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How many liters of a 0.500 M sucrose (C12H22O11) solution contain 1.5 kg of sucrose?

Chapter 13, Problem 75P

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QUESTION:

How many liters of a 0.500 M sucrose \(\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right)\) solution contain 1.5 kg of sucrose?

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QUESTION:

How many liters of a 0.500 M sucrose \(\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right)\) solution contain 1.5 kg of sucrose?

ANSWER:

 

Step 1 of 3

Molarity of the solution can be calculated by the following formula;

\(\text { Molarity }=\frac{\text { Number of moles of sucrose }}{\text { Volume of solution }}\)

Rearrange the formula (1)

\(\text { Volume of solution }=\frac{\text { Moles of sucrose }}{\text { Molarity }}\)

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