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Consider the reaction:2 K3PO4(aq) + 3 NiCl2(aq) ?

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Problem 91P Chapter 13

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 91P

Consider the reaction:

2 K3PO4(aq) + 3 NiCl2(aq) → Ni3(PO4)2(s) + 6 KCl(aq)

What volume of 0.225 M K3PO4 solution is necessary to completely react with 134 mL of 0.0112 M NiCl2?

Step-by-Step Solution:
Step 1 of 3

Solution: Here, we are going to calculate the volume of K3PO4 solution.

Step1:

Molarity(M) is defined as number of moles of solute dissolved in one litre (or one cubic decimetre) of solution.

                                                   Moles of solute

                                Molarity = -------------------------------        ------(1)

                                              Volume of solution in litre

Step2:

Given, Volume of NiCl2 solution = 134 mL = 134 / 1000 L = 0.134 L        [1000 mL = 1 L]

        Molarity of NiCl2 solution = 0.0112 M

Therefore, number of moles of NiCl2 solution = molarity x volume of solution in litres

                                                = 0.0112 M x 0.134 L

                                                = 0.0015008 mol

Step3:

The given reaction...

Step 2 of 3

Chapter 13, Problem 91P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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