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Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro
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Determine the pH of each two-component solution.a. 0.0550

Chapter 15, Problem 139E

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QUESTION:

Determine the pH of each two-component solution.

a. 0.0550 M in HI and 0.00850 M in HF

b. 0.112 M in NaCl and 0.0953 M in KF

c. 0.132 M in \(\mathrm{NH}_{4} \mathrm{Cl}\) and 0.150 M \(\mathrm{HNO}_{3}\)

d. 0.0887 M in sodium benzoate and 0.225 M in potassium bromide

e. 0.0450 M in HCl and 0.0225 M in \(\mathrm{HNO}_{3}\)

Questions & Answers

QUESTION:

Determine the pH of each two-component solution.

a. 0.0550 M in HI and 0.00850 M in HF

b. 0.112 M in NaCl and 0.0953 M in KF

c. 0.132 M in \(\mathrm{NH}_{4} \mathrm{Cl}\) and 0.150 M \(\mathrm{HNO}_{3}\)

d. 0.0887 M in sodium benzoate and 0.225 M in potassium bromide

e. 0.0450 M in HCl and 0.0225 M in \(\mathrm{HNO}_{3}\)

ANSWER:

Problem 139EDetermine the pH of each two-component solution.a. 0.0550 M in HI and 0.00850 M in HFb. 0.112 M in NaCl and 0.0953 M in KFc. 0.132 M in and 0.150 Md. 0.0887 M in sodium benzoate and 0.225 M in potassium bromidee. 0.0450 M in HCl and 0.0225 M in Step by step solutionStep 1 of 5(a)0.0550 M in HI and 0.00850 M in HFHI is a strong acid and HF is a weak base . So, the dissociation of HF is suppressed by the strongdissociation.Therefore, major contribution towards pH is from HI.Let’s calculate the pHTherefore, the pH of the solution is 1.26.___________________________________________________________________\n

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