Solution Found!
Recall, from this chapter, that the factor gamma
Chapter 17, Problem 7P(choose chapter or problem)
Recall from this chapter that the factor gamma \((\gamma)\) governs both time dilation and length contraction, where
\(\gamma=\frac{1}{\sqrt{1-\left(\frac{v^2}{c^2}\right)}}\)
When you multiply the time in a moving frame by \(\gamma\), you get the longer (dilated) time in your fixed frame. When you divide the length in a moving frame by \(\gamma\), you get the shorter (contracted) length in your fixed frame.
If the bus in problem 40 were to slow to a “mere” 10% of the speed of light, show that you would measure the passenger’s catnap to last slightly more than 5 minutes.
Problem 40
A passenger on an interplanetary express bus traveling at v = 0.99c takes a 5-minute catnap, according to her watch. Show that her catnap from the vantage point of a fixed planet lasts 35 minutes.
Questions & Answers
QUESTION:
Recall from this chapter that the factor gamma \((\gamma)\) governs both time dilation and length contraction, where
\(\gamma=\frac{1}{\sqrt{1-\left(\frac{v^2}{c^2}\right)}}\)
When you multiply the time in a moving frame by \(\gamma\), you get the longer (dilated) time in your fixed frame. When you divide the length in a moving frame by \(\gamma\), you get the shorter (contracted) length in your fixed frame.
If the bus in problem 40 were to slow to a “mere” 10% of the speed of light, show that you would measure the passenger’s catnap to last slightly more than 5 minutes.
Problem 40
A passenger on an interplanetary express bus traveling at v = 0.99c takes a 5-minute catnap, according to her watch. Show that her catnap from the vantage point of a fixed planet lasts 35 minutes.
ANSWER:In First part problem is not fully given. According to theory of relativity time dilation is a difference of elapsed time between two events as measured by observer either moving relative to each other or