(II) When a high jumper is in a position such that his arms and lower legs are hanging | StudySoup

Textbook Solutions for Physics: Principles with Applications

Chapter 7 Problem 56P

Question

(II) When a high jumper is in a position such that his arms and lower legs are hanging vertically, and his thighs, trunk, and head are horizontal, calculate how far below the torso’s median line the CM will be. Will this CM be outside the body? Use Table 7–1

Solution

Solution 56P

Step 1 of 2:

A person stands in a position such that his hands and the legs are hanging vertically and the head, neck, trunk are lined up horizontally. We are going to find the center of mass below the median line.

The distance between the median line and the percentage of mass of each part of the body are given by

The distance to head from the median line xh1 = 0

The mass of the head mh1 = 6.9 %

The distance to neck and trunk from the median line xn = 0

The mass of the trunk and neck mn = 46.1 %

The distance from the median line to upper arm xua = 81.2 - 71.7 = 9.5%

The mass of the upper arm mua = 6.6%

The distance from the median line to lower arm xla = 81.2 - 55.3 = 25.9%

The mass of the lower arm mla = 4.2%

The distance from the median line to hands xh2 = 81.2 - 43.1 = 38.1%

The mass of the hands mh2 = 1.7%

The distance from the median line to upper legs xul = 52.1 - 42.5 = 9.6%

The mass of the upper legs mul = 21.5%

The distance from the median line to lower legs xll = 52.1 - 18.2 = 33.9%

The mass of the lower legs mll = 9.6%

The distance from the median line to feet xf = 52.1 - 1.8 = 50.3%

The mass of the feet mf = 3.4%

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full solution

Title Physics: Principles with Applications 6 
Author Douglas C. Giancoli
ISBN 9780321569837

(II) When a high jumper is in a position such that his arms and lower legs are hanging

Chapter 7 textbook questions

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