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Solved: A helicopter carrying Dr. Evil takes off with a
Chapter 2, Problem 89P(choose chapter or problem)
Problem 89P
A helicopter carrying Dr. Evil takes off with a constant upward acceleration of 5.0 m/s2. Secret agent Austin Powers jumps on just as the helicopter lifts off the ground. After the two men struggle for 10.0 s, Powers shuts off the engine and steps out of the helicopter. Assume that the helicopter is in free fall after its engine is shut off, and ignore the effects of air resistance. (a) What is the maximum height above ground reached by the helicopter? (b) Powers deploys a jet pack strapped on his back 7.0 s after leaving the helicopter, and then he has a constant downward acceleration with magnitude 2.0 m/s2. How far is Powers above the ground when the helicopter crashes into the ground?
Questions & Answers
QUESTION:
Problem 89P
A helicopter carrying Dr. Evil takes off with a constant upward acceleration of 5.0 m/s2. Secret agent Austin Powers jumps on just as the helicopter lifts off the ground. After the two men struggle for 10.0 s, Powers shuts off the engine and steps out of the helicopter. Assume that the helicopter is in free fall after its engine is shut off, and ignore the effects of air resistance. (a) What is the maximum height above ground reached by the helicopter? (b) Powers deploys a jet pack strapped on his back 7.0 s after leaving the helicopter, and then he has a constant downward acceleration with magnitude 2.0 m/s2. How far is Powers above the ground when the helicopter crashes into the ground?
ANSWER:
Solution 89P
Step 1 of 7:
(a) What is the maximum height above ground reached by the helicopter?
For the initial step, helicopter starts at rest from the ground and to find the helicopter's height at the top of its trajectory:
Using S = ut +
Where S is height, u is initial velocity , a is acceleration and t is time taken.
Since it starts from rest, u=0 s , t = 10s and a= 5
Using this data in above equation,
S = 0 +
S = 250 m
Therefore, helicopter engine is turned off at 250 m.