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Solved: Fluorine reacts with hydrogen (H) and deuterium
Chapter 2, Problem 97P(choose chapter or problem)
Fluorine reacts with hydrogen (H) and deuterium (D) to form hydrogen fluoride (HF) and deuterium fluoride (DF), where deuterium \(\left({ }_{1}^{2} \mathrm{H}\right)\) is an isotope of hydrogen. Would a given amount of fluorine react with different masses of the two hydrogen isotopes? Does this violate the law of definite proportion? Explain.
Questions & Answers
QUESTION:
Fluorine reacts with hydrogen (H) and deuterium (D) to form hydrogen fluoride (HF) and deuterium fluoride (DF), where deuterium \(\left({ }_{1}^{2} \mathrm{H}\right)\) is an isotope of hydrogen. Would a given amount of fluorine react with different masses of the two hydrogen isotopes? Does this violate the law of definite proportion? Explain.
ANSWER:Step 1 of 3
Here we have to find out the amount of F react with the two isotopes of H-atom is same or different and does this reaction violate the law of definite proportion.
Law of definite proportion:-
The Law of definite proportion states that a given chemical compound always has its component elements in fixed ratio (by mass) and is independent of its source and method of preparation.