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Solved: Fluorine reacts with hydrogen (H) and deuterium

Chapter 2, Problem 97P

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QUESTION:

Fluorine reacts with hydrogen (H) and deuterium (D) to form hydrogen fluoride (HF) and deuterium fluoride (DF), where deuterium \(\left({ }_{1}^{2} \mathrm{H}\right)\) is an isotope of hydrogen. Would a given amount of fluorine react with different masses of the two hydrogen isotopes? Does this violate the law of definite proportion? Explain.

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QUESTION:

Fluorine reacts with hydrogen (H) and deuterium (D) to form hydrogen fluoride (HF) and deuterium fluoride (DF), where deuterium \(\left({ }_{1}^{2} \mathrm{H}\right)\) is an isotope of hydrogen. Would a given amount of fluorine react with different masses of the two hydrogen isotopes? Does this violate the law of definite proportion? Explain.

ANSWER:

Step 1 of 3

Here we have to find out the amount of F react with the two isotopes of H-atom is same or different and does this reaction violate the law of definite proportion.

Law of definite proportion:-

The Law of definite proportion states that a given chemical compound always has its component elements in fixed ratio (by mass) and is independent of its source and method of preparation.

 

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