Solution Found!
Answer: A gaseous reaction takes place at constant volume
Chapter 5, Problem 166P(choose chapter or problem)
A gaseous reaction takes place at constant volume and constant pressure in a cylinder shown here Which of the following equations best describes the reaction? The initial temperature (\(T_{1}\)) is twice that of the final temperature (\(T_{2}\)).
(a) \(A+B \rightarrow C\)
(b) \(A B \rightarrow C+D\)
(c) \(A+B \rightarrow C+D\)
(d) \(A+B \rightarrow 2 C+D\)
Questions & Answers
QUESTION:
A gaseous reaction takes place at constant volume and constant pressure in a cylinder shown here Which of the following equations best describes the reaction? The initial temperature (\(T_{1}\)) is twice that of the final temperature (\(T_{2}\)).
(a) \(A+B \rightarrow C\)
(b) \(A B \rightarrow C+D\)
(c) \(A+B \rightarrow C+D\)
(d) \(A+B \rightarrow 2 C+D\)
ANSWER:
Step 1 of 2
Here we have to find out among the given equations which equation best describes the reaction.
Given:
The reaction has been carried out at constant volume and constant pressure in a cylinder as shown in the figure below,
The initial temperature () = 2
Final temperature =
The given equations are,
(a) A + B C
(b) AB C + D
(c) A + B C + D
(d) A + B 2C + D