Solution Found!
Answer: Calculate the standard enthalpy of formation for
Chapter 6, Problem 101P(choose chapter or problem)
Calculate the standard enthalpy of formation for diamond, given that
\(\mathrm{C}(\text { graphite })+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)\)
\(\Delta H^{\circ}=-393.5\ \mathrm{kJ} / \mathrm{mol}\)
\(\mathrm{C}(\text { diamond })+\mathrm{O}_{2}(\mathrm{g})+\mathrm{CO}_{2}(\mathrm{g})\)
\(\Delta H^{\circ}=-395.4\ \mathrm{kJ} / \mathrm{mol}\)
Questions & Answers
QUESTION:
Calculate the standard enthalpy of formation for diamond, given that
\(\mathrm{C}(\text { graphite })+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)\)
\(\Delta H^{\circ}=-393.5\ \mathrm{kJ} / \mathrm{mol}\)
\(\mathrm{C}(\text { diamond })+\mathrm{O}_{2}(\mathrm{g})+\mathrm{CO}_{2}(\mathrm{g})\)
\(\Delta H^{\circ}=-395.4\ \mathrm{kJ} / \mathrm{mol}\)
ANSWER:Step 1 of 2
Here we have to calculate the standard enthalpy of formation for diamond, given that
C (diamond) + O2(g) ? CO2 (g) = -395.4 KJ/mol