Solution Found!
Answer: For each of the following pairs of hydrogen
Chapter 7, Problem 69P(choose chapter or problem)
For each of the following pairs of hydrogen orbitals, indicate which is higher in energy: (a) 1s, 2s; (b) 2p, 3p; (c) \(3 d_{x y},\ 3 d_{y z}\); (d) 3s, 3d; (e) 4f, 5s.
Questions & Answers
QUESTION:
For each of the following pairs of hydrogen orbitals, indicate which is higher in energy: (a) 1s, 2s; (b) 2p, 3p; (c) \(3 d_{x y},\ 3 d_{y z}\); (d) 3s, 3d; (e) 4f, 5s.
ANSWER:Step 1 of 6
The energy of electron in the hydrogen atom is given by
En= -RH
Here, R is the Rydberg constant
‘n’ is the principal quantum number.
According to that equation electron in the hydrogen atom depends only on the principal quantum number .
The increasing order of energies for hydrogen atom is as follows.
1s< 2s = 2p < 3s = 3p =3d < 4s =4p = 4d = 4f <.............