At a given instant the body of mass m has an angular velocity V and its mass center has a velocity vG. Show that its kinetic energy can be represented as T = 1 2 IICv2 , where IIC is the moment of inertia of the body determined about the instantaneous axis of zero velocity, located a distance rG>IC from the mass center as shown.
Read moreTable of Contents
1
General Principles
2
Force Vectors
3
Equilibrium of a Particle
4
Force System Resultants
5
Equilibrium of a Rigid Body
6
Structural Analysis
7
Internal Forces
8
Friction
9
Center of Gravity and Centroid
10
Moments of Inertia
11
Virtual Work
12
Kinematics of a Particle
13
Kinetics of a Particle: Force and Acceleration
14
Kinetics of a Particle: Work and Energy
15
Kinetics of a Particle: Impulse and Momentum
16
Planar Kinematics of a Rigid Body
17
Planar Kinematics of a Rigid Body: Force and Acceleration
18
Planar Kinetics of a Rigid Body: Work and Energy
19
Planar Kinetics of a Rigid Body: Impulse and Momentum
20
Three-dimensional Kinematics of a Rigid Body
21
Three-dimensional Kinetics of a Rigid Body
22
Vibrations
Textbook Solutions for Engineering Mechanics: Statics & Dynamics
Chapter 18 Problem 18-45
Question
The 12-kg slender rod is attached to a spring, which has an unstretched length of 2 m. If the rod is released from rest when u = 30, determine its angular velocity at the instant u = 90.
Solution
The first step in solving 18 problem number 45 trying to solve the problem we have to refer to the textbook question: The 12-kg slender rod is attached to a spring, which has an unstretched length of 2 m. If the rod is released from rest when u = 30, determine its angular velocity at the instant u = 90.
From the textbook chapter Planar Kinetics of a Rigid Body: Work and Energy you will find a few key concepts needed to solve this.
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full solution
full solution
Title
Engineering Mechanics: Statics & Dynamics 14
Author
Russell C. Hibbeler
ISBN
9780133951929