Solution Found!
Answer: If a horizontal force of F = 50 N is applied
Chapter 8, Problem 8-68(choose chapter or problem)
If a horizontal force of F = 50 N is applied perpendicular to the handle of the lever at E, determine the clamping force developed at G. The mean diameter and lead of the single square-threaded screw at C and D are 25 mm and 5 mm, respectively. The coefficient of static friction is \(\mu_{\mathrm{s}}\) = 0.3.
Questions & Answers
QUESTION:
If a horizontal force of F = 50 N is applied perpendicular to the handle of the lever at E, determine the clamping force developed at G. The mean diameter and lead of the single square-threaded screw at C and D are 25 mm and 5 mm, respectively. The coefficient of static friction is \(\mu_{\mathrm{s}}\) = 0.3.
ANSWER:
Step 1 of 5
First, we'll need to determine the axial force in the screw
Note that since there are two screws, the moment equilibrium equation of the screw is
From here we can express as:
….(1)
The moment in the screw is:
r is radius