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Get Full Access to Chemistry: The Central Science - 13 Edition - Chapter 13.7se - Problem 1pe
Get Full Access to Chemistry: The Central Science - 13 Edition - Chapter 13.7se - Problem 1pe

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# Solved: Calculation of Vapor Pressure of a ISBN: 9780321910417 77

## Solution for problem 1PE Chapter 13.7SE

Chemistry: The Central Science | 13th Edition

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Problem 1PE

Calculation of Vapor Pressure of a Solution

Glycerin (C3H8O3) is a nonvolatile nonelectrolyte with a density of 1.26 g/mL at 25 °C. Calculate the vapor pressure at 25 °C of a solution made by adding 50.0 mL of glycerin to 500.0 mL of water. The vapor pressure of pure water at 25 °C is 23.8 torr (Appendix B). and its density is 1.00 g/mL.

The vapor pressure of benzene. C6H6. is 100.0 torr at 26.1 °C. Assuming Raoult's law is obeyed, how many moles of a nonvolatile solute must be added to 100.0 mL of benzene to decrease its vapor pressure by 10.0% at 26.1 °C? The density of benzene is 0.8765 g/cm3.

(a) 0.011237. (b) 0.11237, (c) 0.1248. (d) 0.1282. (e) 8.765.

Step-by-Step Solution:

Problem 1PECalculation of Vapor Pressure of a SolutionGlycerin (C H O ) is a nonvolatile nonelectrolyte with a density of 1.26 g/mL at 25 °C. Calculate 38 3the vapor pressure at 25 °C of a solution made by adding 50.0 mL of glycerin to 500.0 mL ofwater. The vapor pressure of pure water at 25 °C is 23.8 torr (Appendix B). and its density is1.00 g/mL.The vapor pressure of benzene. C H . is6060 torr at 26.1 °C. Assuming Raoult's law is obeyed,how many moles of a nonvolatile solute must be added to 100.0 mL of benzene to decrease itsvapor pressure by 10.0% at 26.1 °C The density of benzene is 0.8765 g/cm . 3(a) 0.011237. (b) 0.11237, (c) 0.1248. (d) 0.1282. (e) 8.765. Step-by-step solution Step 1 of 2 Raoult’s law: The partial pressure exerted by solvent on the solution is equal to the product ofmole fraction of solvent and vapor pressure of pure solvent and express as follows 0P solution= X solvent P solventThe vapor pressure of pure benzene is 100.0 torr and after adding a non volatile solute thevapor pressure of solution is 10.0% decreases means the vapor pressure of that solution is 90.0torr.

Step 2 of 2

##### ISBN: 9780321910417

The full step-by-step solution to problem: 1PE from chapter: 13.7SE was answered by , our top Chemistry solution expert on 09/04/17, 09:30PM. This textbook survival guide was created for the textbook: Chemistry: The Central Science, edition: 13. Since the solution to 1PE from 13.7SE chapter was answered, more than 569 students have viewed the full step-by-step answer. The answer to “Calculation of Vapor Pressure of a SolutionGlycerin (C3H8O3) is a nonvolatile nonelectrolyte with a density of 1.26 g/mL at 25 °C. Calculate the vapor pressure at 25 °C of a solution made by adding 50.0 mL of glycerin to 500.0 mL of water. The vapor pressure of pure water at 25 °C is 23.8 torr (Appendix B). and its density is 1.00 g/mL.The vapor pressure of benzene. C6H6. is 100.0 torr at 26.1 °C. Assuming Raoult's law is obeyed, how many moles of a nonvolatile solute must be added to 100.0 mL of benzene to decrease its vapor pressure by 10.0% at 26.1 °C? The density of benzene is 0.8765 g/cm3.(a) 0.011237. (b) 0.11237, (c) 0.1248. (d) 0.1282. (e) 8.765.” is broken down into a number of easy to follow steps, and 120 words. This full solution covers the following key subjects: pressure, vapor, Density, Benzene, Water. This expansive textbook survival guide covers 305 chapters, and 6352 solutions. Chemistry: The Central Science was written by and is associated to the ISBN: 9780321910417.

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