Solved: Calculation of Vapor Pressure of a

Problem 1PECalculation of Vapor Pressure of a SolutionGlycerin (C H O ) is a nonvolatile nonelectrolyte with a density of 1.26 g/mL at 25 °C. Calculate 38 3the vapor pressure at 25 °C of a solution made by adding 50.0 mL of glycerin to 500.0 mL ofwater. The vapor pressure of pure water at 25 °C is 23.8 torr (Appendix B). and its density is1.00 g/mL.The vapor pressure of benzene. C H . is6060 torr at 26.1 °C. Assuming Raoult's law is obeyed,how many moles of a nonvolatile solute must be added to 100.0 mL of benzene to decrease itsvapor pressure by 10.0% at 26.1 °C The density of benzene is 0.8765 g/cm . 3(a) 0.011237. (b) 0.11237, (c) 0.1248. (d) 0.1282. (e) 8.765. Step-by-step solution Step 1 of 2 Raoult’s law: The partial pressure exerted by solvent on the solution is equal to the product ofmole fraction of solvent and vapor pressure of pure solvent and express as follows 0P solution= X solvent P solventThe vapor pressure of pure benzene is 100.0 torr and after adding a non volatile solute thevapor pressure of solution is 10.0% decreases means the vapor pressure of that solution is 90.0torr.