Use Table 3.1 to compute the temperatures of solid A and solid B when qA = 1. Then compute both temperatures when qA = 60. Express your answers in terms of ϵ/k, and then in kelvins assuming that ϵ = 0.1 eV.

Solution

Step 1

The small scale system here is consider qA and qB as continuous variables, so the partial derived approximately. The large system however, the quanta merge into a continuous energy variable U so we can write..

The unit entropy are J/K .This derivative has the dimensions of 1/k or reciprocal of temperature. We can define the temperature.

The quantum energy has a value of =0.1ev=1.06

The solids at qA=60 by calculating the slope

qA=59 and qA=61

For B qB=100-qA so the energy points are.

qB=39 and qB=41