Let X1,X2, . . . ,Xn be a random sample from the normal
Chapter 8, Problem 6E(choose chapter or problem)
Let \(X_{1}, X_{2}, \ldots, X_{n}\) be a random sample from the normal distribution \(N(\mu, 9)\). To test the hypothesis \(H_{0}:\) \(\mu=80\) against \(H_{1}: \mu \neq 80\), consider the following three critical regions: \(C_{1}=\left\{\bar{x}: \bar{x} \geq c_{1}\right\}, C_{2}=\left\{\bar{x}: \bar{x} \leq c_{2}\right\}\), and \(C_{3}=\left\{\bar{x}:|\bar{x}-80| \geq c_{3}\right\}\).
(a) If \(n=16\), find the values of \(c_{1}, c_{2}, c_{3}\) such that the size of each critical region is \(0.05\). That is, find \(c_{1}, c_{2}\), \(c_{3}\) such that
\(\begin{aligned}0.05 &=P\left(\bar{X} \in C_{1} ; \mu=80\right)=P\left(\bar{X} \in C_{2} ; \mu=80\right) \\&=P\left(\bar{X} \in C_{3} ; \mu=80\right)\end{aligned}\)
(b) On the same graph paper, sketch the power functions for these three critical regions.
Equation Transcription:
Text Transcription:
X_1,X_2,…,X_n
N(mu,9).
H_0: mu=80
H_1:munot = 80
C_1={bar x: bar x > or = c_1,C_2={bar x: bar x < or = c_2}
C_3={ bar x:| bar x -80| > or = c_3}.
n=16
c_1,c_2,c_3
0.05.
0.05 =P( bar X in C_1;mu=80)=P(bar X in C_2; mu=80) =P( bar X in C_3;=80)
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer