A 76.0-kg person is being pulled away from a burning | StudySoup

Textbook Solutions for College Physics

Chapter 4 Problem 42

Question

A 76.0-kg person is being pulled away from a burning building as shown in Figure 4.41. Calculate the tension in the two ropes if the person is momentarily motionless. Include a free-body diagram in your solution.

                

Figure 4.41 The force \(\mathrm{T}_{2}\) needed to hold steady the person being rescued from the fire is less than her weight and less than the force \(\mathrm{T}_{1}\) in the other rope, since the more vertical rope supports a greater part of her weight (a vertical force).

Solution

 

Step 1 of  2

The tension in the two ropes can be calculated from the free body diagram as shown in the figure below.

Since the person is momentarily motionless ,tension in the string is in static equilibrium. So,

the sum of all  forces acting in x and y direction are zero. 

\(\Sigma x=0\) and \(\Sigma y=0\)

Therefore, \(\Sigma x=0=-T_{1} \cos 75^{\circ}+T_{2} \cos 10^{\circ}\)

                  \(\Sigma y=0=T_{1} \sin 75^{\circ}+T_{2} \sin 10^{\circ}-W\)

where, \(\mathrm{T}_{1}\) and \(\mathrm{T}_{1}\) are tension in the two ropes.

            W = Weight of the person = m g

            \(\mathrm{m}=75 \mathrm{~kg}\)

           \(\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^{2}\)

 

Subscribe to view the
full solution

Title College Physics  1 
Author Paul Peter Urone, Roger Hinrichs
ISBN 9781938168000

A 76.0-kg person is being pulled away from a burning

Chapter 4 textbook questions

×

Login

Organize all study tools for free

Or continue with
×

Register

Sign up for access to all content on our site!

Or continue with

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back