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Why do refrigerators, air conditioners, and heat pumps

Chapter 15, Problem 25

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QUESTION:

Problem 25CQ

Why do refrigerators, air conditioners, and heat pumps operate most cost-effectively for cycles with a small difference between Th and Tc ? (Note that the temperatures of the cycle employed are crucial to its COP .)

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QUESTION:

Problem 25CQ

Why do refrigerators, air conditioners, and heat pumps operate most cost-effectively for cycles with a small difference between Th and Tc ? (Note that the temperatures of the cycle employed are crucial to its COP .)

ANSWER:

Solution  25CQ

Step 1 of 3

The efficiency of a Carnot engine can be obtained as:

              ηhp     =  1-

                   

This is same as the efficiency of a heat pump

The efficiency of the same can also be written as:  ηhp =

Hence when the temperature difference of the source and the sink increases, the work supplied must also increase, for the same heat to be supplied.

Hence for a given constant work input, (which is the general case) a heat pump works better at for a lower temperature difference.

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