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Physics / Introduction to Electrodynamics 4 / Chapter 9 / Problem 18P

Introduction to Electrodynamics | 4th Edition | ISBN: 9780321856562 | Authors: David J. Griffiths

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The index of refraction of diamond is 2.42. Construct the

Chapter 9, Problem 18P

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QUESTION:

The index of refraction of diamond is 2.42. Construct the graph analogous to Fig. 9.16 for the air/diamond interface. (Assume \(\mu_{1}=\mu_{2}=\mu_{0}\).) In particular, calculate (a) the amplitudes at normal incidence, (b) Brewster’s angle, and (c) the “crossover” angle, at which the reflected and transmitted amplitudes are equal.

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QUESTION:

The index of refraction of diamond is 2.42. Construct the graph analogous to Fig. 9.16 for the air/diamond interface. (Assume \(\mu_{1}=\mu_{2}=\mu_{0}\).) In particular, calculate (a) the amplitudes at normal incidence, (b) Brewster’s angle, and (c) the “crossover” angle, at which the reflected and transmitted amplitudes are equal.

ANSWER:

Step 1 of 6

Given the refractive indices of diamond ( ${\mu{}}_{1}={\mu{}}_{2}={\mu{}}_{0}$ )

The graph analogous to given fig(9.16) for air/diamond interface is given below

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