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The index of refraction of diamond is 2.42. Construct the

Introduction to Electrodynamics | 4th Edition | ISBN: 9780321856562 | Authors: David J. Griffiths ISBN: 9780321856562 45

Solution for problem 18P Chapter 9

Introduction to Electrodynamics | 4th Edition

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Introduction to Electrodynamics | 4th Edition | ISBN: 9780321856562 | Authors: David J. Griffiths

Introduction to Electrodynamics | 4th Edition

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Problem 18P

Problem 18P

The index of refraction of diamond is 2.42. Construct the graph analogous to Fig. 9.16 for the air/diamond interface. (Assume μ1 = μ2 = μ0.) In particular, calculate (a) the amplitudes at normal incidence, (b) Brewster’s angle, and (c) the “crossover” angle, at which the reflected and transmitted amplitudes are equal.

Figure 9.16

Step-by-Step Solution:

Solution 18P

Step 1:  Given the refractive indices of diamond ()

        The graph analogous to given fig(9.16) for air/diamond interface is given below

                

Step 2 of 6

Chapter 9, Problem 18P is Solved
Step 3 of 6

Textbook: Introduction to Electrodynamics
Edition: 4
Author: David J. Griffiths
ISBN: 9780321856562

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The index of refraction of diamond is 2.42. Construct the