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Twenty students are asked to select an integer between 1
Chapter 3, Problem 185SE(choose chapter or problem)
Problem 185SE
Twenty students are asked to select an integer between 1 and 10. Eight choose either 4, 5 or 6.
a If the students make their choices independently and each is as likely to pick one integer as any other, what is the probability that 8 or more will select 4,5 or 6?
b Having observed eight students who selected 4, 5, or 6, what conclusion do you draw based on your answer to part (a)?
Questions & Answers
QUESTION:
Problem 185SE
Twenty students are asked to select an integer between 1 and 10. Eight choose either 4, 5 or 6.
a If the students make their choices independently and each is as likely to pick one integer as any other, what is the probability that 8 or more will select 4,5 or 6?
b Having observed eight students who selected 4, 5, or 6, what conclusion do you draw based on your answer to part (a)?
ANSWER:
Solution :
Step 1 of 2:
Let n denotes 20 students asked to select an integer between 1 and 10.
Here n=20
p=and
q=1-p
q=1-0.3
q=0.7
Our goal is:
a). We need to find the probability that 8 or more will select 4,5 or 6.
b). We observed 8 students who selected 4,5, or 6.We need to conclude our answer to part (a).
a).
If the students make their choices independently and each is as likely to pick one integer as any other, then we have to find the probability that 8 or more will select 4,5 or 6.
We know that n=20, p=0.3 and q=0.7.
The formula for the binomial probability is
P(X=a)=
Then the probability that 8 or more is
P(X8)= P(X=8)+P(X=9)+P(X=10)+,...,+P(X=20)
P(X8)=
We know that n=20, p=0.30.
Where, P(X=8),P(X=9),P(X=10),...,P(X=20) is obtained from Excel by using the function “=Binomdist(x,n,p,false)”
Then the table is given below.
X |
P(X8) |
8 |
0.11439674 |
9 |
0.065369566 |
10 |
0.030817081 |
11 |
0.012006655 |
12 |
0.003859282 |
13 |
0.001017833 |
14 |
0.000218107 |
15 |
3.73898E-05 |
16 |
5.00756E-06 |
17 |
5.04964E-07 |
18 |
3.60688E-08 |
19 |
1.62717E-09 |
20 |
3.48678E-11 |
Total |
0.227728203 |
P(X8)= P(X=8)+P(X=9)+P(X=10)+,...,+P(X=20)
P(X8)= 0.11439+0.065369+0.030817,...,3.48678E-11
P(X8)= 0.2277
Therefore the probability that 8 or more will select 4,5 or 6 is 0.2277.