Solution: A current-carrying gold wire has diameter 0.84 mm. | StudySoup

Textbook Solutions for University Physics with Modern Physics (1)

Chapter 25 Problem 25.21

Question

A current-carrying gold wire has diameter 0.84 mm. The electric field in the wire is 0.49 V>m. What are (a) the current carried by the wire; (b) the potential difference between two points in the wire 6.4 m apart; (c) the resistance of a 6.4-m length of this wire?

Solution

Step 1 of 3)

The first step in solving 25 problem number 45 trying to solve the problem we have to refer to the textbook question: A current-carrying gold wire has diameter 0.84 mm. The electric field in the wire is 0.49 V>m. What are (a) the current carried by the wire; (b) the potential difference between two points in the wire 6.4 m apart; (c) the resistance of a 6.4-m length of this wire?
From the textbook chapter Current, resistanCe, and eleCtromotive ForCe you will find a few key concepts needed to solve this.

Step 2 of 7)

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Title University Physics with Modern Physics (1) 14 
Author Hugh D. Young Roger A. Freedman
ISBN 9780321973610

Solution: A current-carrying gold wire has diameter 0.84 mm.

Chapter 25 textbook questions

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