If a simple pendulum oscillates with small amplitude and its length is doubled, what happens to the frequency of its motion? (a) It doubles. (b) It becomes !2 times as large. (c) It becomes half as large. (d) It becomes 1/!2 times as large. (e) It remains the same.
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Textbook Solutions for Physics for Scientists and Engineers with Modern Physics
Question
A 0.500-kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of 10.0 cm. Calculate the maximum value of its (a) speed and (b) acceleration, (c) the speed and (d) the acceleration when the object is 6.00 cm from the equilibrium position, and (e) the time interval required for the object to move from x 5 0 to x 5 8.00 cm.
Solution
The first step in solving 15 problem number 19 trying to solve the problem we have to refer to the textbook question: A 0.500-kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of 10.0 cm. Calculate the maximum value of its (a) speed and (b) acceleration, (c) the speed and (d) the acceleration when the object is 6.00 cm from the equilibrium position, and (e) the time interval required for the object to move from x 5 0 to x 5 8.00 cm.
From the textbook chapter Oscillatory Motion you will find a few key concepts needed to solve this.
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