If a simple pendulum oscillates with small amplitude and its length is doubled, what happens to the frequency of its motion? (a) It doubles. (b) It becomes !2 times as large. (c) It becomes half as large. (d) It becomes 1/!2 times as large. (e) It remains the same.
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Textbook Solutions for Physics for Scientists and Engineers with Modern Physics
Question
A 200-g block is attached to a horizontal spring and executes simple harmonic motion with a period of 0.250 s. The total energy of the system is 2.00 J. Find (a) the force constant of the spring and (b) the amplitude of the motion.
Solution
The first step in solving 15 problem number 22 trying to solve the problem we have to refer to the textbook question: A 200-g block is attached to a horizontal spring and executes simple harmonic motion with a period of 0.250 s. The total energy of the system is 2.00 J. Find (a) the force constant of the spring and (b) the amplitude of the motion.
From the textbook chapter Oscillatory Motion you will find a few key concepts needed to solve this.
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