Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. One force is 9.0 N, acting due east, and the other is 8.0 N, acting 623 north of west. What is the magnitude of the bodys acceleration?
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Question
While two forces act on it, a particle is to move at the constant velocity \(\vec{v}=(3 \mathrm{m} / \mathrm{s}) \hat{i}-(4 \mathrm{m} / \mathrm{s}) \hat{\mathrm{j}}\). One of the forces is \(\vec{F}_{1}=(2 N) \hat{i}+(-6 N) \hat{j}\). What is the other force?
Solution
The first step in solving 5 problem number 4 trying to solve the problem we have to refer to the textbook question: While two forces act on it, a particle is to move at the constant velocity \(\vec{v}=(3 \mathrm{m} / \mathrm{s}) \hat{i}-(4 \mathrm{m} / \mathrm{s}) \hat{\mathrm{j}}\). One of the forces is \(\vec{F}_{1}=(2 N) \hat{i}+(-6 N) \hat{j}\). What is the other force?
From the textbook chapter you will find a few key concepts needed to solve this.
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