Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. One force is 9.0 N, acting due east, and the other is 8.0 N, acting 623 north of west. What is the magnitude of the bodys acceleration?
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Question
Three astronauts, propelled by jet backpacks, push and guide a 120 kg asteroid toward a processing dock, exerting the forces shown in Fig. 5-29, with \(F_{1}=32 \mathrm{N}, F_{2}=55 \mathrm{N}\), \(F_{3}=41 \mathrm{N}\), \(\theta_{1}=30^{\circ}\), and \(\theta_{3}=60^{\circ}\). What is the asteroid’s acceleration
(a) in unit-vector notation and as
(b) a magnitude and
(c) a direction relative to the positive direction of the x axis?
Solution
Step 1 of 4
From Newton’s second law of motion, the net force \(\overrightarrow F\) acting on an object is equal to the mass m of the object multiplied by the acceleration \(\overrightarrow a\) of the object attained by the force.
\(\overrightarrow F = m\overrightarrow a\) ……….(1)
Here, the mass m is given as 120 kg.
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