Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. One force is 9.0 N, acting due east, and the other is 8.0 N, acting 623 north of west. What is the magnitude of the bodys acceleration?
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Chapter 5 Problem 35
Question
The velocity of a 3.00 kg particle is given by " (8.00t + 3.00t 2 ) m/s, with time t in seconds.At the instant the net force on the particle has a magnitude of 35.0 N, what are the direction (relative to the positive direction of the x axis) of (a) the net force and (b) the particles direction of travel?
Solution
Step 1 of 3 a) The velocity of the particle is, So the acceleration of the particle is, The magnitude of acceleration is, The force acting on the particle is given by, Given, mass of the particle Net force acting on the particle, So, That is, Implies,\n .............(1)
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Title
Fundamentals of Physics 10
Author
David Halliday; Robert Resnick; Jearl Walker
ISBN
9781118230725