Prove that if n is an integer, then n2 3n + 5 is odd.
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Textbook Solutions for Discrete Mathematics
Question
In the proof of Result 3.28 it was proved, for integers m and n, that if mn is odd, then m and n are both odd. This was done using a proof by contrapositive. In the proof that was given, it was assumed, without loss of generality, that m is even. Give a proof of this implication, using a proof by cases namely: Case 1. m is even . Case 2. n is even.
Solution
The first step in solving 3.4 problem number 12 trying to solve the problem we have to refer to the textbook question: In the proof of Result 3.28 it was proved, for integers m and n, that if mn is odd, then m and n are both odd. This was done using a proof by contrapositive. In the proof that was given, it was assumed, without loss of generality, that m is even. Give a proof of this implication, using a proof by cases namely: Case 1. m is even . Case 2. n is even.
From the textbook chapter Proof by Cases you will find a few key concepts needed to solve this.
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