(Recommended) Suppose Ax = AX. If A = 0 then X is in the nUllspace. If A i 0 then x is
Chapter 6, Problem 26(choose chapter or problem)
(Recommended) Suppose Ax = AX. If A = 0 then X is in the nUllspace. If A i 0 then x is in the column space. Those spaces have dimensions (n - r) + r = n. So why doesn't every square matrix have n linearly independent eigenvectors?
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer