Another interpretation of the Q of a resonance comes from | StudySoup

Textbook Solutions for Classical Mechanics

Chapter 5 Problem 5.44

Question

Another interpretation of the \(Q\) of a resonance comes from the following: Consider the motion of a driven damped oscillator after any transients have died out, and suppose that it is being driven close to resonance, so you can set \(\omega=\omega_{\mathrm{o}}\). (a) Show that the oscillator's total energy (kinetic plus potential) is \(E=\frac{1}{2} m \omega^{2} A^{2}\). (b) Show that the energy \(\Delta E_{\text {dis }}\) dissipated during one cycle by the damping force \(F_{\mathrm{dmp}}\) is \(2 \pi m \beta \omega A^{2}\). (Remember that the rate at which a force does work is \(Fv\).) (c) Hence show that \(Q\) is \(2 \pi\) times the ratio \(E / \Delta E_{\text {dis }}\).

Solution

Step 1 of 7

(a)

The displacement of a driven damped oscillator is given as,

 \(x=A \cos (\omega t-\delta)\)        

Here, A is the amplitude, \(\omega\) is the angular frequency, t is the time and \(\delta\) is the phase constant.

The amplitude of an oscillator driven by a sinusoidal force with variable frequency is given as,

\(A=\frac{f_{\mathrm{o}}}{\sqrt{\left(\omega_{\mathrm{o}}^{2}-\omega^{2}\right)+4 \beta^{2} \omega^{2}}}\)     

Here, \(\omega_{\mathrm{o}}\) is the natural angular frequency, \(\beta\) is the decay parameter and \(f_{\mathrm{o}}\) is the Fourier coefficient.

The velocity of the particle is given as,

\(v=\frac{d x}{d t}\)

Substitute \(A \cos (\omega t-\delta)\) for x,

\(\begin{aligned} v & =\frac{d}{d t}[A \cos (\omega t-\delta)] \\ & =-A \omega \sin (\omega t-\delta) \end{aligned}\)

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full solution

Title Classical Mechanics 0 
Author John R Taylor
ISBN 9781891389221

Another interpretation of the Q of a resonance comes from

Chapter 5 textbook questions

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