Give an example of a nonincreasing sequence with a limit.
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Textbook Solutions for Calculus: Early Transcendentals
Question
Crossover point The sequence \(\{n !\}\) ultimately grows faster than the sequence \(\left\{b^{n}\right\}\) for any b >1 as \(n \rightarrow \infty\). However, \(b^{n}\) is generally greater than \(n !\) for small values of n. Use a calculator to determine the smallest value of n such that \(n !>b^{n}\) for each of the cases b = 2, b = e, and b = 10.
Solution
The first step in solving 8.2 problem number trying to solve the problem we have to refer to the textbook question: Crossover point The sequence \(\{n !\}\) ultimately grows faster than the sequence \(\left\{b^{n}\right\}\) for any b >1 as \(n \rightarrow \infty\). However, \(b^{n}\) is generally greater than \(n !\) for small values of n. Use a calculator to determine the smallest value of n such that \(n !>b^{n}\) for each of the cases b = 2, b = e, and b = 10.
From the textbook chapter Sequences you will find a few key concepts needed to solve this.
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