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Determine the pOH of each solution and classify it as acidic, basic, or neutral.(a)

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 80P Chapter 14

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 80P

Determine the pOH of each solution and classify it as acidic, basic, or neutral.

(a) [OH−] = 4.5 × 10−2 M

(b) [OH−] = 3.1 × 10−12 M

(c) [OH−] = 5.4 × 10−5 M

(d) [OH−] = 1.2 × 10−2 M

Step-by-Step Solution:

Solution 80P:

Here, we are going to calculate the pOH of each solution and identify whether the reaction is acidic, basic and neutral.

We know,  the ion product constant Kw for water is

Kw =[H3O+][OH-] = 1x10-14

pH + pOH =14

And pOH =  - log[OH- ] and pH = - log[H+ ]

(a) [OH] = 4.5 × 10−2 M

Step 1: We know,

pOH =  - log[OH- ]

        = -log(4.5 × 10−2 )

          = 2 -log4.5

          = 2 -0.653

        =1.35

The pOH of the solution is 1.35

Step 2 of 3

Chapter 14, Problem 80P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Determine the pOH of each solution and classify it as acidic, basic, or neutral.(a)