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As shown in the drawing, the half-angle of the shock wave
Chapter 11, Problem 7P(choose chapter or problem)
As shown in the drawing, the half-angle of the shock wave cone generated by a supersonic airplane is \(45^{\circ}\). What is the speed of the plane relative to the speed of sound?
Questions & Answers
QUESTION:
As shown in the drawing, the half-angle of the shock wave cone generated by a supersonic airplane is \(45^{\circ}\). What is the speed of the plane relative to the speed of sound?
ANSWER:Step 1 of 2
Consider the given data as follows.
The half-angle of the shock wave cone generated by a supersonic airplane is \(\theta = 45^\circ \).
The ratio of the speed of the airplane to the speed of sound is defined as follows.
\(\frac{{{v_{airplane}}}}{{{v_{sound}}}} = \frac{1}{{\sin \theta }}\;\;\;\;\;...\;\left( 1 \right)\)
Here, \({v_{airplane}}\) is the speed of the airplane, and \({v_{sound}}\) is the speed of the sound.