The average translational kinetic energy of an atom | StudySoup

Textbook Solutions for Physics: Principles with Applications

Chapter 29 Problem 39P

Question

The average translational kinetic energy of an atom or molecule is about \(\mathrm{KE} =\frac{3}{2} k T\) (see Section 13-9), where \(k=1.38 \times 10^{-23} \mathrm{~J} / \mathrm{K}\) is Boltzmann's constant. At what temperature T will KE be on the order of the bond energy (and hence the bond easily broken by thermal motion) for (a) a covalent bond (say \(\mathrm{H}_2\)) of binding energy 4.0 eV, and (b) a "weak" hydrogen bond of binding energy 0.12 eV?

Solution

Step 1 of 3)

The first step in solving 29 problem number trying to solve the problem we have to refer to the textbook question: The average translational kinetic energy of an atom or molecule is about \(\mathrm{KE} =\frac{3}{2} k T\) (see Section 13-9), where \(k=1.38 \times 10^{-23} \mathrm{~J} / \mathrm{K}\) is Boltzmann's constant. At what temperature T will KE be on the order of the bond energy (and hence the bond easily broken by thermal motion) for (a) a covalent bond (say \(\mathrm{H}_2\)) of binding energy 4.0 eV, and (b) a "weak" hydrogen bond of binding energy 0.12 eV?
From the textbook chapter Molecules and Solids you will find a few key concepts needed to solve this.

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full solution

Title Physics: Principles with Applications 7 
Author Douglas C. Giancoli
ISBN 9780321625922

The average translational kinetic energy of an atom

Chapter 29 textbook questions

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