A hollow, conducting sphere with an outer radius of 0.250 | StudySoup

Textbook Solutions for University Physics

Chapter 22 Problem 21E

Question

A hollow, conducting sphere with an outer radius of 0.250 m and an inner radius of 0.200 m has a uniform surface charge density of +6.37 X 10-6 C/m2. A charge of -0.500 µC is now introduced at the center of the cavity inside the sphere. (a) What is the new charge density on the outside of the sphere? (b) Calculate the strength of the electric field just outside the sphere. (c) What is the electric flux through a spherical surface just inside the inner surface of the sphere?

Solution

Solution 21E We are given the surface charge density, from this we can calculate the charge on the sphere. Given, outer radius r = 0.250 m Surface area = 4r 2 = 4 × 3.14 × (0.250) m = 0.785 m 2 out 6 2 Surface charge density = 6.37 × 10 C/m Therefore, charge on the sphere 2 6 2 6 = 0.785 m × 6.37 × 10 C/m = 5.00 × 10 C = 5.00 C A charge of -0.500 µC is now introduced at

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full solution

Title University Physics 13 
Author Hugh D. Young, Roger A. Freedman
ISBN 9780321675460

A hollow, conducting sphere with an outer radius of 0.250

Chapter 22 textbook questions

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