Suppose that k events B1,...., Bk form a partition of the sample space S. For i=1,...,k, let Pr(Bi) denote the prior probability of Bi. Also for each event A such that Pr(A) > 0, let (Bi|A) denote the posterior probability of Bi given that the event A has occured. Prove that if Pr(B1|A)<Pr(Bi|A)>Pr(Bi) for at least one value of i(i=2,...,k).
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Textbook Solutions for Probability and Statistics
Question
Consider a machine that produces items in sequence. Under normal operating conditions, the items are independent with probability 0.01 of being defective. However, it is possible for the machine to develop a memory in the following sense: After each defective item, and independent of anything that happened earlier, the probability that the next item is defective is 2/5. After each nondefective item, and independent of anything that happened earlier, the probability that the next item is defective is 1/165. Assume that the machine is either operating normally for the whole time we observe or has a memory for the whole time that we observe. Let B be the event that the machine is operating normally, and assume that Pr(B) = 2/3. Let Di be the event that the ith item inspected is defective. Assume that D1 is independent of B. a. Prove that Pr(Di) = 0.01 for all i. Hint: Use induction. b. Assume that we observe the first six items and the event that occurs is E = Dc 1 Dc 2 D3 D4 Dc 5 Dc 6. That is, the third and fourth items are defective, but the other four are not. Compute Pr(B|D).
Solution
The first step in solving 2.3 problem number 16 trying to solve the problem we have to refer to the textbook question: Consider a machine that produces items in sequence. Under normal operating conditions, the items are independent with probability 0.01 of being defective. However, it is possible for the machine to develop a memory in the following sense: After each defective item, and independent of anything that happened earlier, the probability that the next item is defective is 2/5. After each nondefective item, and independent of anything that happened earlier, the probability that the next item is defective is 1/165. Assume that the machine is either operating normally for the whole time we observe or has a memory for the whole time that we observe. Let B be the event that the machine is operating normally, and assume that Pr(B) = 2/3. Let Di be the event that the ith item inspected is defective. Assume that D1 is independent of B. a. Prove that Pr(Di) = 0.01 for all i. Hint: Use induction. b. Assume that we observe the first six items and the event that occurs is E = Dc 1 Dc 2 D3 D4 Dc 5 Dc 6. That is, the third and fourth items are defective, but the other four are not. Compute Pr(B|D).
From the textbook chapter Conditional Probability you will find a few key concepts needed to solve this.
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