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IP Referring to Example 28–2 Suppose we change the slit

Chapter 28, Problem 102IP

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QUESTION:

Problem 102IP

IP Referring to Example 28–2 Suppose we change the slit separation to a value other than 8.5 × 10−5m, with the result that the linear distance to the tenth bright fringe above the central bright fringe increases from 12 cm to 18 cm. The screen is still 2.3 m from the slits, and the wavelength of the light is 440 nm. (a) Did we increase or decrease the slit separation? Explain, (b) Find the new slit separation.

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QUESTION:

Problem 102IP

IP Referring to Example 28–2 Suppose we change the slit separation to a value other than 8.5 × 10−5m, with the result that the linear distance to the tenth bright fringe above the central bright fringe increases from 12 cm to 18 cm. The screen is still 2.3 m from the slits, and the wavelength of the light is 440 nm. (a) Did we increase or decrease the slit separation? Explain, (b) Find the new slit separation.

ANSWER:

Step 1 of 3

(a) Light travels through two slits and is seen on a screen at a distance of  from the slits. If we take a look at the equation

Implies,

From the above equation it is very clear that the diffraction angle  and the slit separation  are inversely related.

So we can conclude if the distance between the tenth maximum and the central maximum is increased, the slit separation will decrease.

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