Solved: The blood alcohol (C2H5OH) level can be determined by titrating a sample of | StudySoup

Textbook Solutions for Chemistry

Chapter 18 Problem 18.139

Question

The blood alcohol (C2H5OH) level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr31(aq) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr2O7 22) is orange in solution, and the Cr31 ion is green. The unbalanced redox equation is Cr2O7 22 1aq2 1 C2H5OH1aq2 h Cr31 1aq2 1 CO2 1g2 If 31.05 mL of 0.0600 M potassium dichromate solution is required to titrate 30.0 g blood plasma, determine the mass percent of alcohol in the blood.

Solution

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The first step in solving 18 problem number 139 trying to solve the problem we have to refer to the textbook question: The blood alcohol (C2H5OH) level can be determined by titrating a sample of blood plasma with an acidic potassium dichromate solution, resulting in the production of Cr31(aq) and carbon dioxide. The reaction can be monitored because the dichromate ion (Cr2O7 22) is orange in solution, and the Cr31 ion is green. The unbalanced redox equation is Cr2O7 22 1aq2 1 C2H5OH1aq2 h Cr31 1aq2 1 CO2 1g2 If 31.05 mL of 0.0600 M potassium dichromate solution is required to titrate 30.0 g blood plasma, determine the mass percent of alcohol in the blood.
From the textbook chapter Electrochemistry you will find a few key concepts needed to solve this.

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Title Chemistry 9 
Author Steven S. Zumdahl, Susan A. Zumdahl
ISBN 9781133611097

Solved: The blood alcohol (C2H5OH) level can be determined by titrating a sample of

Chapter 18 textbook questions

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