What product would you expect from a nucleophilic substitution reaction of (R)-1-bromo-1-phenylethane with cyanide ion, \(\mathrm {^-C \equiv N}\), as nucleophile? Show the stereochemistry of both reactant and product, assuming that inversion of configuration occurs. Equation Transcription: Text Transcription: ^-C equiv N Na^{+ -}C equiv N
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Textbook Solutions for Organic Chemistry
Question
Amines are converted into alkenes by a two-step process called Hofmann elimination. \(\mathrm {S_N2}\) reaction of the amine with an excess of \(\mathrm {CH_3I}\) in the first step yields an intermediate that undergoes E2 reaction when treated with silver oxide as base. Pentylamine, for example, yields 1-pentene. Propose a structure for the intermediate, and explain why it readily undergoes elimination.
Solution
The first step in solving 11 problem number 84 trying to solve the problem we have to refer to the textbook question: Amines are converted into alkenes by a two-step process called Hofmann elimination. \(\mathrm {S_N2}\) reaction of the amine with an excess of \(\mathrm {CH_3I}\) in the first step yields an intermediate that undergoes E2 reaction when treated with silver oxide as base. Pentylamine, for example, yields 1-pentene. Propose a structure for the intermediate, and explain why it readily undergoes elimination.
From the textbook chapter Reactions of Alkyl Halides: Nucleophilic Substitutions and Eliminations you will find a few key concepts needed to solve this.
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