The amount of energy required to spin-flip a nucleus depends both on the strength of the external magnetic field and on the nucleus. At a field strength of 4.7 T, rf energy of 200 MHz is required to bring a \(\mathrm {^1H}\) nucleus into resonance, but energy of only 187 MHz will bring a \(\mathrm {^{19}F}\) nucleus into resonance. Calculate the amount of energy required to spin-flip a 19F nucleus. Is this amount greater or less than that required to spin-flip a \(\mathrm {^1H}\) nucleus? Equation Transcription: Text Transcription: ^1H ^{19}F ^1H
Read moreTable of Contents
Textbook Solutions for Organic Chemistry
Question
Propose structures for compounds that it the following \(\mathrm {^1H~NMR}\) data:
(a) \(\mathrm {C_4H_6Cl_2}\)
\(2.18~ \delta \) (3 H, singlet)
\(4.16~ \delta \) (2 H, doublet, \(J=7~ \mathrm{Hz}\))
\(5.71~ \delta \) (1 H, triplet, \(J=7~ \mathrm{Hz}\))
(b) \(\mathrm {C_{10}H_{14}}\)
\(1.30~ \delta\) (9 H, singlet)
\(7.30~ \delta\) (5 H, singlet)
(c) \(\mathrm {C_{4}H_{7}BrO}\)
\(2.11~ \delta\) (3 H, singlet)
\(3.52~ \delta\) (2 H, triplet, \(J=6~ \mathrm {Hz}\))
\(4.40~ \delta\) (2 H, triplet, \(J=6~ \mathrm {Hz}\))
(d) \(\mathrm {C_9H_{11}Br}\)
\(2.15~ \delta \) (2 H, quintet, \(J=7~ \mathrm {Hz}\))
\(2.75~ \delta \) (2 H, triplet, \(J=7~ \mathrm {Hz}\))
\(3.38~ \delta \) (2 H, triplet, \(J=7~ \mathrm {Hz}\))
\(7.22~ \delta\) (5 H, singlet)
Solution
The first step in solving 13 problem number 58 trying to solve the problem we have to refer to the textbook question: Propose structures for compounds that it the following \(\mathrm {^1H~NMR}\) data:(a) \(\mathrm {C_4H_6Cl_2}\) \(2.18~ \delta \) (3 H, singlet) \(4.16~ \delta \) (2 H, doublet, \(J=7~ \mathrm{Hz}\)) \(5.71~ \delta \) (1 H, triplet, \(J=7~ \mathrm{Hz}\))(b) \(\mathrm {C_{10}H_{14}}\) \(1.30~ \delta\) (9 H, singlet) \(7.30~ \delta\) (5 H, singlet)(c) \(\mathrm {C_{4}H_{7}BrO}\) \(2.11~ \delta\) (3 H, singlet) \(3.52~ \delta\) (2 H, triplet, \(J=6~ \mathrm {Hz}\)) \(4.40~ \delta\) (2 H, triplet, \(J=6~ \mathrm {Hz}\))(d) \(\mathrm {C_9H_{11}Br}\) \(2.15~ \delta \) (2 H, quintet, \(J=7~ \mathrm {Hz}\)) \(2.75~ \delta \) (2 H, triplet, \(J=7~ \mathrm {Hz}\)) \(3.38~ \delta \) (2 H, triplet, \(J=7~ \mathrm {Hz}\)) \(7.22~ \delta\) (5 H, singlet)
From the textbook chapter Structure Determination: Nuclear Magnetic Resonance Spectroscopy you will find a few key concepts needed to solve this.
Visible to paid subscribers only
Step 3 of 7)Visible to paid subscribers only
full solution