Solution Found!
A particle’s velocity is described by the function vx = t
Chapter 2, Problem 30P(choose chapter or problem)
Problem 30P
A particle’s velocity is described by the function vx = t 2 − 7t + 10 m/s, where t is in s.
a. At what times does the particle reach its turning points?
b. What is the particle’s acceleration at each of the turning points?
Questions & Answers
QUESTION:
Problem 30P
A particle’s velocity is described by the function vx = t 2 − 7t + 10 m/s, where t is in s.
a. At what times does the particle reach its turning points?
b. What is the particle’s acceleration at each of the turning points?
ANSWER:
Step 1 of 2
We have find at what times does the particle reach its turning points, if it's velocity is described by the function \(v_{x}=t^{2}-7 t+10\), where \(t\) is in \(\mathrm{s}\).
A point in the motion where a particle reverses direction is called a turning point. It is a point where the velocity is instantaneously zero while the position is a maximum or minimum.
Thus, the time \((t)\) at which the particle reaches its turning points can be found by solving the equation for with
.
Hence, At \(t=2 s\) and \(t=5 s\),
Therefore, the particle reaches its turning points at \(t=2 s\) and \(t=5 s\).