Section 12.1 Rotational MotionA high-speed drill reaches

Chapter 12, Problem 2E

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QUESTION:

Problem 2E

Section 12.1 Rotational Motion

A high-speed drill reaches 2000 rpm in 0.50 s.

a. What is the drill’s angular acceleration?

b. Through how many revolutions does it turn during this first 0.50 s?

Questions & Answers

QUESTION:

Problem 2E

Section 12.1 Rotational Motion

A high-speed drill reaches 2000 rpm in 0.50 s.

a. What is the drill’s angular acceleration?

b. Through how many revolutions does it turn during this first 0.50 s?

ANSWER:

Step 1 of 2

We have to find the drill's angular acceleration.

The drill's angular acceleration can be found in the expression.

\(\alpha=\frac{\omega_{f}-\omega_{i}}{t}\)

where,

\(\omega_{i}=\text { initial angular velocity }=0 \mat

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