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Section 12.1 Rotational MotionA high-speed drill reaches
Chapter 12, Problem 2E(choose chapter or problem)
QUESTION:
Problem 2E
Section 12.1 Rotational Motion
A high-speed drill reaches 2000 rpm in 0.50 s.
a. What is the drill’s angular acceleration?
b. Through how many revolutions does it turn during this first 0.50 s?
Questions & Answers
QUESTION:
Problem 2E
Section 12.1 Rotational Motion
A high-speed drill reaches 2000 rpm in 0.50 s.
a. What is the drill’s angular acceleration?
b. Through how many revolutions does it turn during this first 0.50 s?
ANSWER:
Step 1 of 2
We have to find the drill's angular acceleration.
The drill's angular acceleration can be found in the expression.
\(\alpha=\frac{\omega_{f}-\omega_{i}}{t}\)
where,
\(\omega_{i}=\text { initial angular velocity }=0 \mat