Explain why solid \(\mathrm{CO}_{2}\) is referred to as dry ice. Text Transcription: CO_2
Read more- Chemistry / Chemistry: A Molecular Approach 5 / Chapter 24 / Problem 18
Table of Contents
Textbook Solutions for Chemistry: A Molecular Approach
Question
In the pyroxene kanoite, the formula unit has two \(\mathrm{SiO}_{3}^{2-}\) units and is balanced by manganese and magnesium ions. Determine the formula unit of kanoite. Assume that the oxidation state of Mn is +2.
Text Transcription:
SiO_3^2-
Solution
The first step in solving 24 problem number trying to solve the problem we have to refer to the textbook question: In the pyroxene kanoite, the formula unit has two \(\mathrm{SiO}_{3}^{2-}\) units and is balanced by manganese and magnesium ions. Determine the formula unit of kanoite. Assume that the oxidation state of Mn is +2.Text Transcription:SiO_3^2-
From the textbook chapter Chemistry of the Nonmetals you will find a few key concepts needed to solve this.
Visible to paid subscribers only
Step 3 of 7)Visible to paid subscribers only
full solution
?In the pyroxene kanoite, the formula unit has two \(\mathrm{SiO}_{3}^{2-}\) units and
Chapter 24 textbook questions
-
Chapter 24: Problem 9 Chemistry: A Molecular Approach 5 -
Chapter 24: Problem 15 Chemistry: A Molecular Approach 5Silicon bonds to oxygen to form a tetrahedral shape in both the network covalent silica compound, \(\mathrm{SiO}_{2}\), and in ionic silicate compounds. What is the oxidation state of Si in each of these structures? a. silica compound, \(\mathrm{SiO}_{2}\) b. orthosilicates, \(\mathrm{SiO}_{4}^{4-}\) c. pyrosilicates, \(\mathrm{Si}_{2} \mathrm{O}_{7}^{6-}\) Text Transcription: SiO2 SiO4 4- Si2O7 6-
Read more -
Chapter 24: Problem 16 Chemistry: A Molecular Approach 5What is the oxidation state of Si in each of these structures? a. pyroxenes, \(\mathrm{SiO}_{3}^{2-}\) b. amphiboles, \(\mathrm{Si}_{4} \mathrm{O}_{11}^{6-}\) c. phyllosilicates, \(\mathrm{Si}_{2} \mathrm{O}_{5}^{2-}\) Text Transcription: SiO3 2- Si4O11 6- Si2O5 2-
Read more -
Chapter 24: Problem 17 Chemistry: A Molecular Approach 5In the orthosilicate garnet, the formula unit has three \(\mathrm{SiO}_{4}{ }^{4-}\) units and is balanced by \(\mathrm{Ca}^{2+}\) and \(\mathrm{Al}^{3+}\) cations. Determine the formula unit of garnet. Text Transcription: SiO4 4- Ca2+ Al 3+
Read more -
Chapter 24: Problem 18 Chemistry: A Molecular Approach 5In the pyroxene kanoite, the formula unit has two \(\mathrm{SiO}_{3}^{2-}\) units and is balanced by manganese and magnesium ions. Determine the formula unit of kanoite. Assume that the oxidation state of Mn is +2. Text Transcription: SiO_3^2-
Read more -
Chapter 24: Problem 19 Chemistry: A Molecular Approach 5Kaolin is a clay material that is a phyllosilicate. Use charge balancing to determine how many hydroxide ions are in the formula for kaolin, \(\mathrm{Al}_{2} \mathrm{Si}_{2} \mathrm{O}_{5}(\mathrm{OH})_{x}\). Text Transcription: Al_2Si_2O_5(OH)x
Read more -
Chapter 24: Problem 20 Chemistry: A Molecular Approach 5Tremolite is a double-chain silicate in the amphibole class. Use charge balancing to determine how many hydroxide ions are in the formula for tremolite, \(\mathrm{Ca}_{2} \mathrm{Mg}_{5} \mathrm{Si}_{8} \mathrm{O}_{22}(\mathrm{OH})_{x}\). Text Transcription: Ca_2Mg_5Si_8O_22(OH)x
Read more -
Chapter 24: Problem 21 Chemistry: A Molecular Approach 5How are the silica tetrahedrons linked for \(\mathrm{ZrSiO}_{4}\) ? Which class of silicates does this compound belong to? Text Transcription: ZrSiO_4
Read more -
Chapter 24: Problem 22 Chemistry: A Molecular Approach 5How are the silica tetrahedrons linked for \(\mathrm{CaSiO}_{3}\) ? Which class of silicates does this compound belong to? Text Transcription: CaSiO_3
Read more -
Chapter 24: Problem 23 Chemistry: A Molecular Approach 5Predict the structure and give the charges on the cations in one of the minerals in the hornblende family, \(\mathrm{Ca}_{2} \mathrm{Mg}_{4} \mathrm{FeSi}_{7} \mathrm{AlO}_{22}(\mathrm{OH})_{2}\). Text Transcription: Ca_2Mg_4FeSi_7AlO_22(OH)_2
Read more -
Chapter 24: Problem 24 Chemistry: A Molecular Approach 5Predict the structure and label the charges on the cations in the mineral hedenbergite, \(\mathrm{CaFeSi}_{2} \mathrm{O}_{6}\). Text Transcription: CaFeSi_2O_6
Read more -
Chapter 24: Problem 25 Chemistry: A Molecular Approach 5A major source of boron is the mineral kernite, \(\mathrm{Na}_{2}\left[\mathrm{~B}_{4} \mathrm{O}_{5}(\mathrm{OH})_{4}\right] \cdot 3 \mathrm{H}_{2} \mathrm{O}\). Calculate how many grams of boron can be produced from \(1.0 \times 10^{3} \mathrm{~kg}\) of a kernite-bearing ore if the ore contains 0.98 % kernite by mass and the process has a 65 % yield. Text Transcription: Na_2[B_4O_5(OH)_4] dot 3H_2O 1.0 x 10^3 kg
Read more -
Chapter 24: Problem 26 Chemistry: A Molecular Approach 5An uncommon mineral of boron is ulexite, \(\mathrm{NaCaB}_{5} \mathrm{O}_{9} \cdot 8 \mathrm{H}_{2} \mathrm{O}\). How many grams of boron can be produced from \(5.00 \times 10^{2} \mathrm{~kg}\) of ulexite-bearing ore if the ore contains 0.032 % ulexite by mass and the process has an 88 % yield? Text Transcription: NaCaB_5O_9 dot 8H_2O 5.00 x 10^2 kg
Read more -
Chapter 24: Problem 27 Chemistry: A Molecular Approach 5Explain why the bond angles in \(\mathrm{BCl}_{3}\) and \(\mathrm{NCl}_{3}\) are different. Text Transcription: BCl_3 NCl_3
Read more -
Chapter 24: Problem 28 Chemistry: A Molecular Approach 5Explain why the bond between B and Cl in the molecule \(\mathrm{BCl}_{3}\) is shorter than would be expected for a single B-Cl bond. Text Transcription: BCl_3
Read more -
Chapter 24: Problem 29 Chemistry: A Molecular Approach 5Predict the number of vertices and faces on each closo-borane. a. \(\mathrm{B}_{6} \mathrm{H}_{6}^{2-}\) b. \(\mathrm{B}_{12} \mathrm{H}_{12}^{2-}\) Text Transcription: B_6H_6 2- B_12H_12 2-
Read more -
Chapter 24: Problem 30 Chemistry: A Molecular Approach 5Predict the number of vertices and faces on each closo-borane. a. \(\mathrm{B}_{4} \mathrm{H}_{4}^{2-}\) b. \(\mathrm{B}_{9} \mathrm{H}_{9}^{2-}\) Text Transcription: B_4H_4 2- B_9H_9 2-
Read more -
Chapter 24: Problem 36 Chemistry: A Molecular Approach 5Silicon carbide is produced by heating silicone polymers, forming methane gas, hydrogen gas, and silicon carbide. Balance the reaction of heating \(\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{Si}\right]_{8}\) to form silicon carbide. Text Transcription: [(CH_3)_2Si]_8
Read more -
Chapter 24: Problem 37 Chemistry: A Molecular Approach 5Referring to the phase diagram in Section 12.8, describe what happens to the phase of \(\mathrm{CO}_{2}\) during each process. a. reducing the pressure on solid \(\mathrm{CO}_{2}\) that is at \(-80^{\circ} \mathrm{C}\) b. decreasing the temperature on \(\mathrm{CO}_{2}\) gas that is held at a pressure of 20 atm c. increasing the temperature on solid \(\mathrm{CO}_{2}\) that is held at a pressure of 0.8 atm Text Transcription: CO_2 -80^circ C
Read more -
Chapter 24: Problem 38 Chemistry: A Molecular Approach 5Referring to the phase diagram in Section 12.8, describe what happens to the phase of \(\mathrm{CO}_{2}\) during each process: a. reducing the temperature from the critical point b. increasing the pressure on \(\mathrm{CO}_{2}\) gas that is held at a temperature of \(-50^{\circ} \mathrm{C}\) c. increasing the temperature on solid \(\mathrm{CO}_{2}\) that is held at a pressure of 20 atm Text Transcription: CO_2 -50^circ C
Read more -
Chapter 24: Problem 39 Chemistry: A Molecular Approach 5Predict the products for each reaction and write a balanced equation. a. CO( g) + CuO(s) b. \(\mathrm{SiO}_{2}(s)+\mathrm{C}(s)\) c. S(s) + CO( g) Text Transcription: SiO_2(s) + C(s)
Read more -
Chapter 24: Problem 40 Chemistry: A Molecular Approach 5Predict the products for each reaction and write a balanced equation. a. \(\mathrm{CO}(g)+\mathrm{Cl}_{2}(g)\) b. \(\mathrm{CO}_{2}(g)+\mathrm{Mg}(s)\) c. S(s) + C(s) Text Transcription: CO( g) + Cl_2( g) CO_2( g) + Mg(s)
Read more -
Chapter 24: Problem 41 Chemistry: A Molecular Approach 5Give the oxidation state for carbon in: a. CO b. \(\mathrm{CO}_{2}\) c. \(\mathrm{C}_{3} \mathrm{O}_{2}\) Text Transcription: CO_2 C_3O_2
Read more -
Chapter 24: Problem 42 Chemistry: A Molecular Approach 5Write a balanced reaction for the gas release reaction of AlkaSeltzer, sodium bicarbonate with citric acid, \(\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{7}\). (The acid is a triprotic acid and consists of a chain of three carbon atoms, each with a carboxylic acid group, COOH.) Text Transcription: C_6H_8O_7
Read more -
Chapter 24: Problem 49 Chemistry: A Molecular Approach 5Referring to the tables in Appendix IIB, determine whether or not hydrogen azide is stable at room temperature compared to its elements, \(\mathrm{H}_{2}\) and \(\mathrm{N}_{2}\). Is hydrogen azide stable at any temperature? Text Transcription: H_2 N_2
Read more -
Chapter 24: Problem 50 Chemistry: A Molecular Approach 5Referring to the tables in Appendix IIB, determine if dinitrogen monoxide is stable at room temperature compared to its elements, \(\mathrm{O}_{2}\) and \(\mathrm{N}_{2}\). Is dinitrogen monoxide stable at any temperature? Text Transcription: O_2 N_2
Read more -
Chapter 24: Problem 51 Chemistry: A Molecular Approach 5Predict the products for each reaction and write a balanced equation. a. \(\mathrm{NH}_{4} \mathrm{NO}_{3}(a q)+\) heat b. \(\mathrm{NO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)\) c. \(\mathrm{PCl}_{3}(l)+\mathrm{O}_{2}(g)\) Text Transcription: NH_4NO_3(aq) + NO_2( g) + H_2O(l) PCl_3(l) + O_2( g)
Read more -
Chapter 24: Problem 52 Chemistry: A Molecular Approach 5Predict the products for each reaction and write a balanced equation. a. NO(g) + NO2(g) b. heating \(\mathrm{PH}_{3}\) c. \(\mathrm{P}_{4}(s)+5 \mathrm{O}_{2}(g)\) Text Transcription: PH_3 P_4(s) + 5 O_2( g)
Read more -
Chapter 24: Problem 53 Chemistry: A Molecular Approach 5Rank the nitrogen ions from the one with N in the highest oxidation state to the one with N in the lowest. \(\mathrm{N}_{3}{ }^{-}, \mathrm{N}_{2} \mathrm{H}_{5}{ }^{+}, \mathrm{NO}_{3}{ }^{-}, \mathrm{NH}_{4}^{+}, \mathrm{NO}_{2}^{-}\) Text Transcription: N_3 -, N_2H_5 +, NO_3 -, NH_4 +, NO_2 -
Read more -
Chapter 24: Problem 54 Chemistry: A Molecular Approach 5Determine the oxidation state of N in the compounds in the reaction for the formation of nitric acid. Identify the oxidizing agent and the reducing agent. \(3 \mathrm{NO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2 \mathrm{HNO}_{3}(l)+\mathrm{NO}(g)\) Text Transcription: 3 NO_2( g) + H_2O(l) longrightarrow 2 HNO_3(l) + NO( g)
Read more -
Chapter 24: Problem 55 Chemistry: A Molecular Approach 5Draw the Lewis structures for the phosphorus halides \(\mathrm{PCl}_{3}\) and \(\mathrm{PCl}_{5}\). Describe their VSEPR shape. Text Transcription: PCl_3 PCl_5
Read more -
Chapter 24: Problem 56 Chemistry: A Molecular Approach 5Dinitrogen pentoxide is an ionic compound formed from the ions \(\mathrm{NO}_{2}{ }^{+}\) and \(\mathrm{NO}_{3}{ }^{-}\). Give the oxidation state of N in each ion and the VSEPR shape for each of the ions. Text Transcription: NO2 + NO3 -
Read more -
Chapter 24: Problem 57 Chemistry: A Molecular Approach 5Ammonium carbonate is produced from the reaction of urea, \(\mathrm{CO}\left(\mathrm{NH}_{2}\right)_{2}\) with water. Write a balanced equation for this reaction and determine how much urea is needed to produce 23 g of ammonium carbonate. Text Transcription: CO(NH_2)_2
Read more -
Chapter 24: Problem 58 Chemistry: A Molecular Approach 5Explain why phosphine, \(\mathrm{PH}_{3}\), is less polar than ammonia. Text Transcription: PH_3
Read more -
Chapter 24: Problem 59 Chemistry: A Molecular Approach 5Reacting oxygen with white phosphorus can form either \(\mathrm{P}_{4} \mathrm{O}_{6}\) or \(\mathrm{P}_{4} \mathrm{O}_{10}\). State the conditions that determine which product forms. Text Transcription: P_4O_6 P_4O_10
Read more -
Chapter 24: Problem 60 Chemistry: A Molecular Approach 5\(\mathrm{P}_{4} \mathrm{O}_{10}\) is one of the most effective drying agents, having the ability to extract water from other molecules. The \(\mathrm{P}_{4} \mathrm{O}_{10}\) forms phosphoric acid. Write balanced reactions for the reaction of \(\mathrm{P}_{4} \mathrm{O}_{10}\) with: a. \(\mathrm{HNO}_{3}\), forming \(\mathrm{N}_{2} \mathrm{O}_{5}\) b. \(\mathrm{H}_{2} \mathrm{SO}_{4}\), forming \(\mathrm{SO}_{3}\) Text Transcription: P_4O_10 HNO_3 N_2O_5 H_2SO_4 SO_3
Read more -
Chapter 24: Problem 63 Chemistry: A Molecular Approach 5Identify each compound as an oxide, peroxide, or superoxide. a. \(\mathrm{LiO}_{2}\) b. CaO c. \(\mathrm{K}_{2} \mathrm{O}_{2}\) Text Transcription: LiO_2 K_2O_2
Read more -
Chapter 24: Problem 64 Chemistry: A Molecular Approach 5Identify each compound as an oxide, peroxide, or superoxide. a. MgO b. \(\mathrm{Na}_{2} \mathrm{O}_{2}\) c. \(\mathrm{CsO}_{2}\) Text Transcription: Na_2O_2 CsO_2
Read more -
Chapter 24: Problem 66 Chemistry: A Molecular Approach 5Sulfur dioxide is a toxic sulfur compound. List one natural source and one industrial source that produce \(\mathrm{SO}_{2}\). Text Transcription: SO_2
Read more -
Chapter 24: Problem 67 Chemistry: A Molecular Approach 5Calculate the maximum mass (in grams) of each metal sulfide that will dissolve in 1.0 L of a solution that is \(5.00 \times 10^{-5} \mathrm{M}\) in \(\mathrm{Na}_{2} \mathrm{~S}\). a. PbS b. ZnS Text Transcription: 5.00 x 10 - 5 M Na_2S
Read more -
Chapter 24: Problem 68 Chemistry: A Molecular Approach 5A coal source contains 1.1% sulfur by mass. If \(2.0 \times 10^{4} \mathrm{~kg}\) of coal is burned and forms oxides, calculate the mass of \(\mathrm{CaSO}_{4}(s)\) that is produced from "scrubbing" the \(\mathrm{SO}_{2}\) pollutant out of the exhaust gas. Assume that all of the sulfur in the coal is converted to calcium sulfate. Text Transcription: 2.0 x 10^4 kg CaSO_4(s) SO_2
Read more -
Chapter 24: Problem 69 Chemistry: A Molecular Approach 5Write the equation for roasting iron pyrite in the absence of air to form elemental sulfur. Calculate the volume of \(S_{2}\) gas that can be produced from roasting 5.5 kg of iron pyrite. Assume that all of the sulfur in the iron pyrite is converted to \(S_{2}\) gas. (Assume STP to calculate the gas volume.) Text Transcription: S_2
Read more -
Chapter 24: Problem 70 Chemistry: A Molecular Approach 5Write an overall reaction from the two steps in the Claus process. Calculate the volume of \(\mathrm{H}_{2} \mathrm{~S}\) gas needed to produce 1.0 kg of S(s). (Assume STP to calculate the gas volume.) Text Transcription: H_2S
Read more -
Chapter 24: Problem 71 Chemistry: A Molecular Approach 5Determine the oxidation state of Xe and give the VSEPR structure for each compound. a. \(\mathrm{XeF}_{2}\) b. \(\mathrm{XeF}_{6}\) c. \(\mathrm{XeOF}_{4}\) Text Transcription: XeF_2 XeF_6 XeOF_4
Read more -
Chapter 24: Problem 72 Chemistry: A Molecular Approach 5Describe the shape of each halogen compound. a. \(\mathrm{BrF}_{4}{ }^{-}\) b. \(\mathrm{IF}_{3}\) c. \(\mathrm{BrO}_{2}{ }^{-}\) d. \(\mathrm{ClO}_{4}{ }^{-}\) Text Transcription: BrF4 - IF3 BrO2 - ClO4 -
Read more -
Chapter 24: Problem 74 Chemistry: A Molecular Approach 5Carbon tetrachloride is produced by passing chlorine gas over carbon disulfide in the presence of a catalyst. The reaction also produces \(\mathrm{S}_{2} \mathrm{Cl}_{2}\). Write the balanced reaction and identify which element is oxidized and which element is reduced. Text Transcription: S_2Cl_2
Read more -
Chapter 24: Problem 75 Chemistry: A Molecular Approach 5If 55 g of \(\mathrm{SiO}_{2}(s)\) glass is placed into 111 L of 0.032 M HF, is there enough HF to dissolve all of the glass? Determine which substance is the limiting reagent and calculate how much of the other reagent is left if the reaction proceeds to completion. Text Transcription: SiO_2(s)
Read more -
Chapter 24: Problem 76 Chemistry: A Molecular Approach 5Describe the difference in the types of bonds (single, double, triple) and the shapes of the following two iodine ions: \(\mathrm{ICl}_{4}{ }^{-}\) and \(\mathrm{IO}_{4}{ }^{-}\). Text Transcription: ICl4 - IO4 -
Read more -
Chapter 24: Problem 77 Chemistry: A Molecular Approach 5From the compositions of lignite and bituminous coal, calculate the mass of sulfuric acid that could potentially form as acid rain from burning \(1.00 \times 10^{2} \mathrm{~kg}\) of each type of coal. Text Transcription: 1.00 x 10^2 kg
Read more -
Chapter 24: Problem 78 Chemistry: A Molecular Approach 5Calculate the volume of \(\mathrm{CO}_{2}\) released from heating and decomposing 88 g of sodium bicarbonate. (Assume standard pressure and temperature.) Text Transcription: CO_2
Read more -
Chapter 24: Problem 79 Chemistry: A Molecular Approach 5All of the halogens form oxoacids. The perhalic acids have the general formula of \(\mathrm{HXO}_{4}\). Explain why \(\mathrm{HClO}_{4}\) is a much stronger acid than \(\mathrm{HIO}_{4}\). Text Transcription: HXO_4 HClO_4 HIO_4
Read more -
Chapter 24: Problem 80 Chemistry: A Molecular Approach 5The halogens form oxoacids with different amounts of oxygen. Explain why \(\mathrm{HClO}_{4}\) is a stronger acid than \(\mathrm{HClO}_{2}\). Text Transcription: HClO_4 HClO_2
Read more -
Chapter 24: Problem 81 Chemistry: A Molecular Approach 5Determine the ratio of effusion rates of HCl compared to each gas. a. \(\mathrm{Cl}_{2}\) b. HF c. HI Text Transcription: CI_2
Read more -
Chapter 24: Problem 82 Chemistry: A Molecular Approach 5Calculate the ratio of effusion rates for each pair of gases. a. \({ }^{238} \mathrm{UF}_{6}\) and ClF b. \({ }^{238} \mathrm{UF}_{6}\) and \({ }^{235} \mathrm{UF}_{6}\) Text Transcription: 238UF_6 238UF_6 235UF_6
Read more -
Chapter 24: Problem 83 Chemistry: A Molecular Approach 5Sodium peroxide is a very powerful oxidizing agent. Balance the reaction of sodium peroxide with elemental iron to give sodium oxide and \(\mathrm{Fe}_{3} \mathrm{O}_{4}\). Text Transcription: Fe_3O_4
Read more -
Chapter 24: Problem 84 Chemistry: A Molecular Approach 5Sulfur dioxide is a reducing agent. When it is bubbled through an aqueous solution containing \(\mathrm{Br}_{2}\), a red-colored solution, it reduces the bromine to colorless bromide ions and forms sulfuric acid. Write a balanced equation for this reaction and identify the oxidizing and reducing agent. Text Transcription: Br_2
Read more -
Chapter 24: Problem 85 Chemistry: A Molecular Approach 5Using the molecular orbital model for a diatomic molecule, explain the different bond lengths for the ions of oxygen. Also state which ion is diamagnetic.
Read more -
Chapter 24: Problem 86 Chemistry: A Molecular Approach 5The closo-borane with the formula \(\mathrm{B}_{6} \mathrm{H}_{6}{ }^{2-}\) has the six B atoms at vertices, forming an octahedron structure with eight faces. The formula for the number of sides is 2n-4, where n is the number of boron atoms. Determine the number of vertices and faces for each closo-borane. a. \(\mathrm{B}_{4} \mathrm{H}_{4}{ }^{2-}\) b. \(\mathrm{B}_{12} \mathrm{H}_{12}{ }^{2-}\) Text Transcription: B_6H_6 2- B_4H_4 2- B_12H_12 2-
Read more -
Chapter 24: Problem 87 Chemistry: A Molecular Approach 5Find the amount (in moles) of C-C bonds that must be broken when 1.0 mole of C(g) is formed from C (diamond). Calculate the \(\Delta H\) of sublimation of diamond from the data in Appendix II, Table B. Then do the calculation using the C-C bond energy in Table 10.3. Suggest a reason for the difference between the two values. Text Transcription: Delta H
Read more -
Chapter 24: Problem 88 Chemistry: A Molecular Approach 5Breathing air that contains 0.13 % CO by volume for 30 minutes will cause death. CO can form by incomplete combustion of carbon-containing compounds. Calculate the minimum volume of octane (\(\mathrm{C}_{8} \mathrm{H}_{18}\), a component of gasoline, which has a density of 0.70 g/mL) that must burn to produce this composition of CO in a garage of volume \(40 \mathrm{~m}^{3}\) at 298 K and 1.0 atm. Text Transcription: C_8H_18 40 m^3
Read more -
Chapter 24: Problem 89 Chemistry: A Molecular Approach 5Given that the \(\Delta H_{\mathrm{f}}^{\circ}\) of \(1 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{3}\) is -633 kJ, use the data in Appendix II, Table B to calculate the \(\Delta H^{\circ}\) for the formation of a 1 M solution of \(\mathrm{SO}_{2}\) in water from \(\mathrm{SO}_{2}(\mathrm{~g})\). Text Transcription: Delta H_f^circ 1 M H_2SO_3 Delta H^circ SO_2 SO_2( g)
Read more -
Chapter 24: Problem 90 Chemistry: A Molecular Approach 5Use the data in Appendix II, Table B to calculate \(\Delta H^{\circ}\) for the formation of a 1 M solution of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) from \(\mathrm{SO}_{3}(g)\). Text Transcription: Delta H^circ H_2SO_4 SO_3( g)
Read more -
Chapter 24: Problem 91 Chemistry: A Molecular Approach 5Calculate the standard enthalpy of reaction for reducing the different forms of iron oxide to iron metal and \(\mathrm{CO}_{2}\) from the reaction of the oxide with CO. Identify which reaction is the most exothermic per mole of iron and explain why. a. \(\mathrm{Fe}_{3} \mathrm{O}_{4}\) b. FeO c. \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) Text Transcription: CO_2 Fe_3O_4 Fe_2O_3
Read more -
Chapter 24: Problem 92 Chemistry: A Molecular Approach 5Balance the equation for the production of acetylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)\) from the reaction of calcium carbide with water. If the acetylene is burned to form water and carbon dioxide, how many kilojoules of energy are produced from the complete reaction of 18 g of calcium carbide? Text Transcription: (C_2H_2)
Read more -
Chapter 24: Problem 93 Chemistry: A Molecular Approach 5Carbon suboxide, \(\mathrm{C}_{3} \mathrm{O}_{2}\), is a linear molecule with the two oxygen atoms at the end and double bonds between each carbon and oxygen atom. a. Draw the Lewis structure for \(\mathrm{C}_{3} \mathrm{O}_{2}\). b. State the type of hybridization of each carbon atom. c. Calculate the heat of reaction for the reaction of carbon suboxide with water to form malonic acid \(\left(\mathrm{HO}_{2} \mathrm{CCH}_{2} \mathrm{CO}_{2} \mathrm{H}\right)\). Hint: Each end of malonic acid has a carbon double bonded to an oxygen and to a hydroxide. Text Transcription: C_3O_2 (HO_2CCH_2CO_2H)
Read more -
Chapter 24: Problem 95 Chemistry: A Molecular Approach 5When hydrazine is dissolved in water, it acts like a base. \(\mathrm{N}_{2} \mathrm{H}_{4}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{N}_{2} \mathrm{H}_{5}^{+}(a q)+\mathrm{OH}^{-}(a q) \\ K_{\mathrm{b}_{1}}=8.5 \times 10^{-7}\) \(\mathrm{N}_{2} \mathrm{H}_{5}^{+}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{N}_{2} \mathrm{H}_{6}^{2+}(a q)+\mathrm{OH}^{-}(a q) \\ K_{\mathrm{b}_{2}}=8.9 \times 10^{-16}\) a. Calculate the \(K_{\mathrm{b}}\) for the overall reaction of hydrazine forming \(\mathrm{N}_{2} \mathrm{H}_{6}{ }^{2+}\). b. Calculate \(K_{\mathrm{a}_{1}}\) for \(\mathrm{N}_{2} \mathrm{H}_{5}{ }^{+}\). c. Calculate the concentration of hydrazine and both cations in a solution buffered at a pH of 8.5 for a solution that was made by dissolving 0.012 mol of hydrazine in 1 L of water. Text Transcription: N_2H_4(aq) + H_2O(l) rightleftharpoons N_2H_5 +(aq) + OH-(aq) Kb_1 = 8.5 x 10-7 N_2H_5 +(aq) + H_2O(l) rightleftharpoons N_2H_6 2+(aq) + OH-(aq) Kb_2 = 8.9 * 10-16 K_b N_2H_6 2+ K_a1 N_2H_5 +.
Read more -
Chapter 24: Problem 96 Chemistry: A Molecular Approach 5Solid fuel in the booster rockets for spacecraft consists of aluminum powder as the fuel and ammonium perchlorate as the oxidizing agent. \(3 \mathrm{NH}_{4} \mathrm{ClO}_{4}(s)+3 \mathrm{Al}(s) \longrightarrow \\ \mathrm{Al}_{2} \mathrm{O}_{3}(s)+\mathrm{AlCl}_{3}(s)+6 \mathrm{H}_{2} \mathrm{O}(g)+3 \mathrm{NO}(g)\) If a rocket launch burns \(2.200 \times 10^{3} \mathrm{~kg}\) of aluminum, calculate the energy produced in joules. Calculate the volume of the gas produced, assuming it was cooled back to 298 K at 1 atm. The standard enthalpy of formation of solid ammonium perchlorate is -295.3 kJ/mol. Text Transcription: 3 NH_4ClO_4(s) + 3 Al(s) longrightarrow Al_2O_3(s) + AlCl_3(s) + 6 H_2O( g) + 3 NO( g) 2.200 x 10^3 kg
Read more -
Chapter 24: Problem 97 Chemistry: A Molecular Approach 5Two known compounds have the formula \(\mathrm{H}_{2} \mathrm{~N}_{2} \mathrm{O}_{2}\). One of them is a weak acid and one is a weak base. The acid, called hyponitrous acid, has two O-H bonds. The base, called nitramide, has no O-H bonds. Draw Lewis structures for these compounds. Predict whether the acid is stronger or weaker than nitrous acid and whether the base is stronger or weaker than ammonia. Text Transcription: H_2N_2O_2
Read more -
Chapter 24: Problem 102 Chemistry: A Molecular Approach 5Explain why \(\mathrm{H}_{2} \mathrm{~S}\) has a different bond angle and is much more reactive than \(\mathrm{H}_{2} \mathrm{O}\). Text Transcription: H_2S H_2O
Read more -
Chapter 24: Problem 105 Chemistry: A Molecular Approach 5Explain why \(\mathrm{SO}_{2}\) is used as a reducing agent but \(\mathrm{SO}_{3}\) is not. Text Transcription: SO_2 SO_3
Read more -
Chapter 24: Problem 106 Chemistry: A Molecular Approach 5Explain why the interhalogen molecule \(\mathrm{BrCl}_{3}\) exists but \(\mathrm{ClBr}_{3}\) does not. Text Transcription: BrCl_3 ClBr_3
Read more -
Chapter 24: Problem 109 Chemistry: A Molecular Approach 5As a group, create a single schematic drawing of a factory that uses the Haber-Bosch process and the Ostwald process to make \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) fertilizer. The factory may only take in \(\mathrm{N}_{2}(g), \mathrm{H}_{2}(g)\), and \(\mathrm{O}_{2}(g)\). Pass your diagram around the group and have each group member add one step in the process. Where might the factory obtain \(\mathrm{H}_{2}\) ? Text Transcription: NH_4NO_3 N2( g), H2( g) O2( g) H_2
Read more -
Chapter 24: Problem 112 Chemistry: A Molecular Approach 5Hydrogen sulfide \(\left(\mathrm{H}_{2} \mathrm{~S}\right)\) smells like rotten eggs; its smell can be detected at concentrations as low as 0.02 ppm. Well water, which is drawn from underground depths of 30-250 meters (100-800 feet), is sometimes contaminated with hydrogen sulfide. The contamination arises from bacterial decomposition of sulfur-containing organic and inorganic matter present in the oxygen-deficient underground environment. Some \(\mathrm{H}_{2} \mathrm{~S}\) gas dissolves in the water that is pumped for drinking supplies, where it is detected by taste at concentrations as low as 0.05 ppm. Municipalities remove \(\mathrm{H}_{2} \mathrm{~S}\) to improve water taste and to prevent the accumulation of toxic \(\mathrm{H}_{2} \mathrm{~S}\) gas within the system. The first table that follows lists hydrogen sulfide solubility in water when the partial pressure of hydrogen sulfide is 1.00 atm. The second table lists solubility product constant data for common metal sulfides. Use the information provided in the tables to answer the following questions: a. What can you conclude about the temperature dependence of \(\mathrm{H}_{2} \mathrm{~S}\) solubility in water? b. Suppose that water analysis indicates that your well's water contains \(1.8 \mathrm{mg} \ \mathrm{H}_{2} \mathrm{~S}\) per liter of well water. Using Henry's law (Chapter 14) and the data in the first table, calculate the partial pressure of \(\mathrm{H}_{2} \mathrm{~S}\), in atm, that exists above your well water at \(25{ }^{\circ} \mathrm{C}\). (Assume the well water is in a closed container). c. Air containing \(\mathrm{H}_{2} \mathrm{~S}\) at 20 ppm (by volume) and below is considered safe to breathe. Is the air above the solution in part b safe to breathe? (The total pressure is 1.00 atm.) d. A water technician recommends that you treat your well water with hydrogen peroxide, \(\mathrm{H}_{2} \mathrm{O}_{2}\), in order to convert \(\mathrm{H}_{2} \mathrm{~S}\) to sulfate (which does not have an offensive odor or taste), according to the following unbalanced reaction: \(\mathrm{H}_{2} \mathrm{O}_{2}(a q)+\mathrm{H}_{2} \mathrm{~S}(a q) \longrightarrow \mathrm{SO}_{4}{ }^{2-}(a q)+\mathrm{H}^{+}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) What volume of a 3.0% by mass solution of hydrogen peroxide is required to treat 955 liters of your well water? (Assume that no other species are present to react with the \(\mathrm{H}_{2} \mathrm{O}_{2}\) and that the density of the hydrogen peroxide solution is 1.0 g/mL.) e. Hydrogen sulfide is a weak diprotic acid that ionizes in water to form hydrogen sulfide \(\left(\mathrm{HS}^{-}\right)\) and sulfide \(\left(\mathrm{S}^{2-}\right)\). Sulfide dissolved in water can be precipitated as an insoluble metal sulfide, according to the following reaction: \(\mathrm{M}^{2+}(a q)+\mathrm{S}^{2-}(a q) \longrightarrow \mathrm{MS}(s)\) Which metal in the second table most effectively removes hydrogen sulfide from water? f. What volume, in mL, of a 0.500 M solution of the metal ion you chose in part e is required to remove the hydrogen sulfide present in 955 liters of your well water (from part b)? g. What mass, in grams, of the metal sulfide (from part f) precipitates? (Assume 100\% yield.) Text Transcription: (H_2S) H_2S 25^circ C H_2O_2 H_2O_2(aq) + H_2S(aq) longrightarrow SO_4 2-(aq) + H+ (aq) + H_2O(l) (HS - ) (S2-) M2 + (aq) + S2-(aq) longrightarrow MS(s)
Read more -
Chapter 24: Problem 1 Chemistry: A Molecular Approach 5Why does BN form compounds similar to those formed by elemental carbon?
Read more -
Chapter 24: Problem 2 Chemistry: A Molecular Approach 5What is the main characteristic that determines whether or not an element is a main-group element?
Read more -
Chapter 24: Problem 3 Chemistry: A Molecular Approach 5Does the metallic characteristic of a main-group element increase or decrease as we move down a family? Explain why?
Read more -
Chapter 24: Problem 4 Chemistry: A Molecular Approach 5Why does silicon form only single bonds with oxygen but carbon, which is in the same family as silicon, forms double bonds with oxygen in many compounds?
Read more -
Chapter 24: Problem 5 Chemistry: A Molecular Approach 5What is the difference between a rock and a mineral?
Read more -
Chapter 24: Problem 6 Chemistry: A Molecular Approach 5Briefly define each term. a. orthosilicate b. amphibole c. pyroxene d. pyrosilicate e. feldspar
Read more -
Chapter 24: Problem 7 Chemistry: A Molecular Approach 5Why is boron oxide often added to silica glass?
Read more -
Chapter 24: Problem 8 Chemistry: A Molecular Approach 5Why does boron form electron-deficient bonds? Provide an example.
Read more -
Chapter 24: Problem 10 Chemistry: A Molecular Approach 5Nitric acid and phosphoric acid are two major chemical products of the chemical industry. Describe some of their uses.
Read more -
Chapter 24: Problem 11 Chemistry: A Molecular Approach 5What is the typical concentration of oxygen in dry air?
Read more -
Chapter 24: Problem 12 Chemistry: A Molecular Approach 5Describe how nitrogen can be separated from the other components of air.
Read more -
Chapter 24: Problem 13 Chemistry: A Molecular Approach 5Earth’s atmosphere originally did not contain oxygen. Explain how the atmosphere gained oxygen.
Read more -
Chapter 24: Problem 14 Chemistry: A Molecular Approach 5Name a benefit, a hazard, and a useful commercial application of ozone.
Read more -
Chapter 24: Problem 31 Chemistry: A Molecular Approach 5Describe the differences among a closo-borane, a nido-borane, and an arachno-borane.
Read more -
Chapter 24: Problem 32 Chemistry: A Molecular Approach 5Describe how boron is used in the nuclear industry.
Read more -
Chapter 24: Problem 33 Chemistry: A Molecular Approach 5Describe the difference between regular charcoal and activated charcoal.
Read more -
Chapter 24: Problem 34 Chemistry: A Molecular Approach 5Explain why the structure of charcoal allows carbon to act as a good filter while the diamond structure does not.
Read more -
Chapter 24: Problem 35 Chemistry: A Molecular Approach 5Describe the difference between an ionic carbide and a covalent carbide. Which types of atoms will form these carbides with carbon?
Read more -
Chapter 24: Problem 43 Chemistry: A Molecular Approach 5Explain the process of fixing nitrogen.
Read more -
Chapter 24: Problem 44 Chemistry: A Molecular Approach 5Explain why the diatomic nitrogen atom is unusable by most plants. Where do plants get nitrogen?
Read more -
Chapter 24: Problem 45 Chemistry: A Molecular Approach 5Describe the differences in the allotropes of white and red phosphorus. Explain why red phosphorus is more stable.
Read more -
Chapter 24: Problem 46 Chemistry: A Molecular Approach 5Describe how red and black phosphorus are made from white phosphorus.
Read more -
Chapter 24: Problem 47 Chemistry: A Molecular Approach 5Saltpeter and Chile saltpeter are two important mineral sources for nitrogen. Calculate the mass percent of nitrogen in each mineral.
Read more -
Chapter 24: Problem 48 Chemistry: A Molecular Approach 5Apatite is a main mineral source for the production of phosphorus. Calculate the atomic and mass percent of P in the mineral apatite.
Read more -
Chapter 24: Problem 61 Chemistry: A Molecular Approach 5Name the major source of the element oxygen and describe how it is produced.
Read more -
Chapter 24: Problem 62 Chemistry: A Molecular Approach 5Explain why either greatly decreasing or increasing the percentage of oxygen in the atmosphere is dangerous.
Read more -
Chapter 24: Problem 65 Chemistry: A Molecular Approach 5Explain why the viscosity of liquid sulfur increases with increasing temperature initially, but then decreases upon further increases in temperature.
Read more -
Chapter 24: Problem 73 Chemistry: A Molecular Approach 5When chlorine is bubbled through a colorless aqueous solution containing bromide ions, the solution turns red and the chlorine is reduced. Write a balanced equation for this reaction and identify the oxidizing and reducing agent.
Read more -
Chapter 24: Problem 94 Chemistry: A Molecular Approach 5Calcium carbonate is insoluble in water. Yet, it dissolves in an acidic solution. Calculate the standard enthalpy, entropy, and Gibbs free energy change for the reaction between solid calcium carbonate and hydrochloric acid. What drives the reaction, the enthalpy change or the entropy change?
Read more -
Chapter 24: Problem 98 Chemistry: A Molecular Approach 5Explain why fine particles of activated charcoal can absorb more (as a filter) than large briquettes of charcoal.
Read more -
Chapter 24: Problem 99 Chemistry: A Molecular Approach 5The two major components of the atmosphere are the diatomic molecules of nitrogen and oxygen. Explain why pure nitrogen is used as a protective atmosphere in the laboratory and pure oxygen is much more reactive.
Read more -
Chapter 24: Problem 100 Chemistry: A Molecular Approach 5Explain why nitrogen can form compounds with many different oxidation numbers.
Read more -
Chapter 24: Problem 101 Chemistry: A Molecular Approach 5Describe how sodium dihydrogen phosphate can be used as a pH buffering agent.
Read more -
Chapter 24: Problem 103 Chemistry: A Molecular Approach 5Explain why fluorine is found only with the oxidation state of -1 or 0, while the other halogens are found in compounds with other oxidation states.
Read more -
Chapter 24: Problem 104 Chemistry: A Molecular Approach 5Why do some substances burn in fluorine gas even if they do not burn in oxygen gas?
Read more -
Chapter 24: Problem 107 Chemistry: A Molecular Approach 5Have each group member select a different element from this list: B, C, N, O, and F. Have all group members look up the following values for their elements: valence electron configuration, covalent atomic radius, effective nuclear charge, first ionization energy, and Pauling electronegativity. All members should compare the values for their elements with those of the group. Repeat with O, S, Se, Te, and Po. Account for the trends you see by referring to quantum-mechanical shells. Note and provide a tentative explanation for any exceptions to trends you observe.
Read more -
Chapter 24: Problem 108 Chemistry: A Molecular Approach 5Provide a detailed chemical description of your birthstone or favorite gem. If two members of the group share a birthstone, have one select another gem, so that no two group members work with the same gem. Is your gem a silicate? What type? Share your findings with your group. Does your group agree on which gem has the most interesting structure?
Read more -
Chapter 24: Problem 110 Chemistry: A Molecular Approach 5Ask each group member to work individually to write out two or three reactions from one section of the chapter. Replace the symbol for the element that is the topic of that section with a blank or an X. Take turns playing “identify the mystery element” as follows. One person shares his or her reactions (with the blanks) with the group. The person to the right of the person sharing tries to identify the missing element. If that person can’t, the group member to the right tries. Continue until either the element has been identified or all group members have had a chance. The next round starts with the person who was first to guess the element sharing reactions with the group. Continue until all have shared reactions and all reactions have been correctly identified.
Read more -
Chapter 24: Problem 111 Chemistry: A Molecular Approach 5Working individually, find a sentence in the chapter that uniquely describes a particular main-group compound. As in the previous question, take turns reading your sentences to the group saying “blank” in place of the name of the compound and giving group members a chance to identify the compound.
Read more