The two metal objects in Fig. 25-24 have net charges of +70 pC and -70 pC, which result in a 20 V Fig.25-24 Problem 1. potential difference between them. (a) What is the capacitance of the system? (b) If the charges are changed to +200 pC and -200 pC, what does the capacitance become? (c) What does the potential difference become?
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Textbook Solutions for Fundamentals of Physics:
Question
If an uncharged parallel-plate capacitor (capacitance C) is connected to a battery, one plate becomes negatively charged as electrons move to the plate face (area A). In Fig. 25-26, the depth d from which the electrons come 0 in the plate in a particular capacitor is plotted against a range of values for the potential difference V of the battery. The density of conduction electrons in the copper plates is 8.49 X 1028 electrons/m3 The vertical scale is set by ds = 1.00 pm, and the horizontal scale is set by Vs = 20.0 V. What is the ratio C/A?
Solution
The first step in solving 25 problem number 7 trying to solve the problem we have to refer to the textbook question: If an uncharged parallel-plate capacitor (capacitance C) is connected to a battery, one plate becomes negatively charged as electrons move to the plate face (area A). In Fig. 25-26, the depth d from which the electrons come 0 in the plate in a particular capacitor is plotted against a range of values for the potential difference V of the battery. The density of conduction electrons in the copper plates is 8.49 X 1028 electrons/m3 The vertical scale is set by ds = 1.00 pm, and the horizontal scale is set by Vs = 20.0 V. What is the ratio C/A?
From the textbook chapter Capacitance you will find a few key concepts needed to solve this.
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