A proton traveling at 23.0 with respect to the direction of a magnetic field of strength 2.60 mT experiences a magnetic force of 6.50 X 10-17 N. Calculate (a) the proton's speed and (b) its kinetic energy in electron-volts.
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Textbook Solutions for Fundamentals of Physics:
Question
In Fig. 28-39, an electron with an initial kinetic energy of 4.0 ke Venters region 1 at time t = O. That region contains a uniform magnetic field directed into the page, with magnitude 0.010 T. The electron goes through a half-circle and then exits region 1, headed toward region 2 across a gap of 25.0 cm. There is an electric potential difference Ll. V = 2000 V across the gap, with a polarity such that the electron's speed increases 11 Region 1 ~ t Region 2 01 2 Fig. 28-39 30. uniformly as it traverses the gap. Region 2 contains a uniform magnetic field directed out of the page, with magnitude 0.020 T. The electron goes through a half-circle and then leaves region 2. At what time t does it leave?
Solution
The first step in solving 28 problem number 30 trying to solve the problem we have to refer to the textbook question: In Fig. 28-39, an electron with an initial kinetic energy of 4.0 ke Venters region 1 at time t = O. That region contains a uniform magnetic field directed into the page, with magnitude 0.010 T. The electron goes through a half-circle and then exits region 1, headed toward region 2 across a gap of 25.0 cm. There is an electric potential difference Ll. V = 2000 V across the gap, with a polarity such that the electron's speed increases 11 Region 1 ~ t Region 2 01 2 Fig. 28-39 30. uniformly as it traverses the gap. Region 2 contains a uniform magnetic field directed out of the page, with magnitude 0.020 T. The electron goes through a half-circle and then leaves region 2. At what time t does it leave?
From the textbook chapter Magnetic Fields you will find a few key concepts needed to solve this.
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