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# A 350-N, uniform, 1.50-m bar is suspended horizontally by ISBN: 9780321675460 31

## Solution for problem 9E Chapter 11

University Physics | 13th Edition

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Problem 9E

A 350-N, uniform, 1.50-m bar is suspended horizontally by two vertical cables at each end. Cable A can support a maximum tension of 500.0 N without breaking, and cable B can support up to 400.0 N. You want to place a small weight on this bar. (a) What is the heaviest weight you can put on without breaking either cable, and (b) where should you put this weight?

Step-by-Step Solution:

Solution 9E Step 1: a) F or equilibrium, the total force will be zero. So, we can write, F + F AF - B = 0g x where , F - Aximum tension of cable A F - maximum tension of cable B B Fg Weight of the rod Fx Maximum weight which it can with stand We are putting negative sign for F and F because it is acting downward g x Therefore, F + FA- F BF g x Provided, F = 500 N A FB 400 N Fg 350 N Therefore, maximum weight the cables can withstand, F = 500 N + 400 N - 350 N = 650 x N

Step 2 of 2

##### ISBN: 9780321675460

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