A 350-N, uniform, 1.50-m bar is suspended horizontally by | StudySoup

Textbook Solutions for University Physics

Chapter 11 Problem 9E

Question

A 350-N, uniform, 1.50-m bar is suspended horizontally by two vertical cables at each end. Cable A can support a maximum tension of 500.0 N without breaking, and cable B can support up to 400.0 N. You want to place a small weight on this bar. (a) What is the heaviest weight you can put on without breaking either cable, and (b) where should you put this weight?

Solution

Solution 9E Step 1: a) F or equilibrium, the total force will be zero. So, we can write, F + F AF - B = 0g x where , F - Aximum tension of cable A F - maximum tension of cable B B Fg Weight of the rod Fx Maximum weight which it can with stand We are putting negative sign for F and F because it is acting downward g x Therefore, F + FA- F BF g x Provided, F = 500 N A FB 400 N Fg 350 N Therefore, maximum weight the cables can withstand, F = 500 N + 400 N - 350 N = 650 x N

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full solution

Title University Physics 13 
Author Hugh D. Young, Roger A. Freedman
ISBN 9780321675460

A 350-N, uniform, 1.50-m bar is suspended horizontally by

Chapter 11 textbook questions

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