Fluid flow The x- and y-components of a fluid moving in two dimensions are given by the following functions u and v. The speed of the fluid at (x, y) is s(x, y) = \(\sqrt{u(x, y)^{2}+v(x, y)^{2}}\). Use the Chain Rule to find \(\partial s / \partial x\) and \(\partial x / \partial y\). u(x,y) = 2y and v(x,y) = -2x; \(x \geq 0 \text { and } y \geq 0\)
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Textbook Solutions for Calculus: Early Transcendentals
Question
Chain Rule with one independent variable Use Theorem 12.7 to find the following derivatives. When feasible, express your answer in terms of the independent variable.
dz/dt, where \(z=\sqrt{r^{2}+s^{2}}, r=\cos 2 t, \text { and } s=\sin 2 t)
Solution
Solution 10E
Step 1 of 3:
In this problem we need to find the derivative of z.
That is , .
Chain rule with one independent variable : Let z be a function of two variables (x , y) ,differentiable on an open domain ‘D’ .Suppose that x and y are functions of a single variable t differentiable on an open interval ‘’ and such that for every
,
.
Then z(x(t),y(t)) is a function of t , differentiable on and we have :
The given function z(r(t),s(t)) is a function of t , differentiable on and we have :
…………(1)
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