An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic waves that travel 1530 m/s in seawater. The time delay of the echo to the ocean floor and back is 6 s. Show that the depth of the water directly below the vessel is 4590 m.
6 s t=6sec= 2 = 3 s v= 1530 m/s We know that d v= t d=v×t =1530×3 =4950 m